How can I optimize my homework solutions for efficiency and accuracy?

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Homework Help Overview

The discussion revolves around optimizing homework solutions related to volume and surface area calculations, likely within a calculus context. Participants are examining the correctness of their answers and the implications of their mathematical reasoning.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the completeness of their answers, particularly regarding the dimensions and the relationship between volume and surface area. Some are exploring the implications of their derivatives and the conditions for minimization.

Discussion Status

Several participants have provided feedback on the original poster's attempts, noting areas where information may be missing or assumptions may need to be reconsidered. There is a mix of suggestions regarding calculation methods and the interpretation of given data.

Contextual Notes

Participants mention specific numerical values and constraints related to the problem, such as the volume being 2500.1055 cm³, which may influence their calculations and assumptions. There is also a reference to entry boxes that may affect how the problem is approached.

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Homework Statement


http://img7.imageshack.us/img7/1826/43544187.jpg


Homework Equations





The Attempt at a Solution


whats wrong with my answers? everything looks right to me... :S
 
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The only thing wrong that I see is that you haven't answered the question. You said that the volume will be minimized. You have given x, but you haven't found y and have not said what the dimensions are.
 
HallsofIvy said:
The only thing wrong that I see is that you haven't answered the question. You said that the volume will be minimized. You have given x, but you haven't found y and have not said what the dimensions are.

y=2500/17.12

the thing is, i only have to choose the right answer from those drop down menu boxes..
so i must of chosen something wrong.. but what? i don't see any mistakes
 
okay my derivatives look fine.. when f'(x)=0 x=17.1
f''(x) > 0 for x>0.. that's right because if plugging in a negative number i will get f''(x) = -..

so what's wrong?
 
can someone please help me?
 
why are u guys ignoring this post? is it something that i said?
for the last part where it says it will be relative min, when x=___
would it be -21.5446 ?
i got it by getting the second derivative equal to 0
 
One of your entry boxes says "This implies that the surface area is given in S only..."
Except for this, everything else it looks fine.

Here's a tip you might consider. Many or most of the problems you have posted have oddball numbers such as a volume of V = 2500.1055 cm^3.
I did all of my calculations using V, and replaced V only in the very last step. This saved my from writing 2500.1055 a bunch of times.

For example, A = x^2 + 4V/x. It's easy to get dA/dx = 2x -4V/x^2. Rewriting this as dA/dx = 2x -4Vx-2, it's easy to get the second derivative and verify that it's positive for all x > 0.
 
Mark44 said:
One of your entry boxes says "This implies that the surface area is given in S only..."
Except for this, everything else it looks fine.

Here's a tip you might consider. Many or most of the problems you have posted have oddball numbers such as a volume of V = 2500.1055 cm^3.
I did all of my calculations using V, and replaced V only in the very last step. This saved my from writing 2500.1055 a bunch of times.

For example, A = x^2 + 4V/x. It's easy to get dA/dx = 2x -4V/x^2. Rewriting this as dA/dx = 2x -4Vx-2, it's easy to get the second derivative and verify that it's positive for all x > 0.


i did it this way.. i substituted V only at the very end and i got the same answers..
and about the "This implies that the surface area is given in S only..." yeah i didnt read it carefully but still. now i got it tnx!
 
Last edited:

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