How can I optimize the area of a roof with a given wall length and angle?

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SUMMARY

The discussion focuses on optimizing the area of a roof given a specific wall length and angle, utilizing mathematical differentiation techniques. The variables defined include wall length (b), half the roof length (a), and the angle (theta). The area formula presented is Area = 2ab*sin(theta/2) + 1/2 a^2*sin(theta). The key takeaway is the need to minimize the perimeter while keeping the area fixed, which requires differentiating the perimeter with respect to the variables involved.

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  • Understanding of basic trigonometry and sine functions.
  • Familiarity with calculus, specifically differentiation techniques.
  • Knowledge of geometric principles related to area and perimeter.
  • Ability to interpret mathematical equations and apply them to real-world problems.
NEXT STEPS
  • Study the principles of optimization in calculus.
  • Learn about the application of differentiation in minimizing functions.
  • Explore geometric properties of triangles and their areas.
  • Investigate the relationship between angles and side lengths in trigonometric functions.
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Students in mathematics or engineering disciplines, particularly those focusing on optimization problems and geometric calculations.

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Homework Statement



[PLAIN]http://img593.imageshack.us/img593/7536/unledci.png

Homework Equations





The Attempt at a Solution



I called the wall b, half the roof a, and the angle theta.
I get Area=2ab*sin(theta/2)+1/2 a^2 sin(theta)... try differentiating with respect to a and theta then setting them to zero.. doesn't do much
 
Last edited by a moderator:
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the question asks you to minimize perimeter (minus the base), not area. the area is fixed and so can be used to reduce the number of variables.
 
Oh I meant differentiate b with respect to a and theta. But yes, you are correct, silly me!
 

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