How can i sketch the graph of a step function

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SUMMARY

The discussion focuses on sketching the graph of a step function, specifically the greatest integer function represented as N(t)=25(2|t+2/2|-t). Participants clarify the mathematical notation and confirm that the function is a floor function, which outputs the greatest integer less than or equal to the input. The analysis reveals that for t-values in the range [2n, 2(n+1)), the function value is n+1, leading to a linear descent in the graph. The conversation emphasizes the importance of precise mathematical expression and understanding of function types.

PREREQUISITES
  • Understanding of step functions and their characteristics
  • Familiarity with floor functions and greatest integer notation
  • Basic knowledge of graph sketching techniques
  • Proficiency in mathematical notation and simplification
NEXT STEPS
  • Study the properties of floor functions in detail
  • Learn how to sketch graphs of piecewise functions
  • Explore the implications of absolute value in mathematical expressions
  • Practice problems involving step functions and their graphical representations
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Mathematics students, educators, and anyone interested in understanding step functions and their graphical representations.

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could you give me the method of sketching the graph of a step function
here is an example:
N(t)=25(2||t+2/2||-t)

thanks a lot for your help
 
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Pleas write maths properly!

Do you mean:
N(t)=25(2|t+\frac{2}{2}|-t)
Or:
N(t)=25(2|\frac{t+2}{2}|-t)
 
second one. sorry don't be very furious since I'm new to the forum
N(t)=25(2|\frac{t+2}{2}|-t)
 
I am only seething a little..

Now, "2" is a positive number!
Can you simplify the product between the "2" and the absolute value expression a bit?
 
no sorry isn't an absolute value
is a step function
 
Okay, is it a floor function (equal to the greatest integer lower than the argument), or a roof function (equal to the smallest integer greater than the argument)?
 
it's a greatest integer function
 
Last edited:
I'm unfamiliar with term "great integer function".

I'll proceed as if it is a floor function:

Now, we see that for t-values 2n\leq{t}&lt;{2(n+1)}[/tex], the floor function has the function value n+1<br /> <br /> Thus, in that interval, we have:<br /> 50(n+1-2(n+1))\leq{N(t)}\leq{50}(n+1-2n), having its maximum value at t=2n, descending linearly to the limiting value -50(n+1) at t=2(n+1)
 
i think the above ans wrong
 
  • #10
mydarshankumar said:
i think the above ans wrong
Would you mind greatly telling why you think that?
 

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