How can I solve 4y''-12y'+9y = 9(x^2-x)?

[Riazy]

Homework Statement

4y''-12y'+9y = 9(x^2-x)

This is the problem that has to be dealt with
we are supposed to get the general solution for it
(yh + yp)

Homework Equations

The Attempt at a Solution

Yh is pretty easy,

We get by completing the square of

r^2-3r + 9/4 We get a double root,

Yh = (C1x + C2)e^3x/2


That was pretty easy, and 1/3 is done

now to Yp which is a bit tricky for me


Yp

Yp= Ax^2+Bx+C (Thats what's assumed)
Yp' = 2Ax + 1
Yp'' = 2A

Inserting it all into the the de

4(2A) - 12 (2Ax + 1) + 9(Ax^2+Bx+C) = 9x^2 -9x

I seem to get the wrong coefficients, could someone help me solve the rest of this problem?
detailed explanations are appreciated, Thanks!

 

[Dick]

Try it! It's not that hard. There's only one x^2 term on each side. Set them equal to each other. What does that tell you about A?

 

[Riazy]

Hmm, I tried, but its an irritating simple error i do somewhere, could you possibly try to solve it too? So I can see how you did it.

 

[Dick]

Hmm, I tried, but its an irritating simple error i do somewhere, could you possibly try to solve it too? So I can see how you did it.

I would like to see that irritatingly simple error. We don't solve problems without seeing an attempt on your part. Expand both sides and set the coefficients of equal powers of x equal.

 

[Mark44]

Hmm, I tried, but its an irritating simple error i do somewhere, could you possibly try to solve it too? So I can see how you did it.

It's good practice to go back through your own work and spot errors.