How can I solve a volume integral question with a trig substitution?

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ppy
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Hi,

I was attempting a volume integral question out of a book. I know what the final answer is and what integral i am supposed to work out but I do not know how I am supposed to solve it. I have tried different ways such as integration by substitution and integration by parts but I do not seem to be getting anywhere.

This is the ∫[itex]^{1}_{-1}[/itex] 4(√(1-x[itex]^{2}[/itex]))(x+1)dx The answer is 2pi.

any help would be great thanks.
 
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This is not a volume integral. Put x=sin u and proceed
 
The integral started out as a triple volume integral. The part mentioned is the final part of the triple integral. I have tried x=sinu and still got nowhere. Is it a simple substitution or do I have to integrate by parts as well ?
Thanks
 
hi ppy! :smile:
ppy said:
I have tried x=sinu and still got nowhere. Is it a simple substitution or do I have to integrate by parts as well ?

davidmoore63@y's :smile: substitution does work …

show us how far you got with it :wink:
 
Thanks. I've got there now !
 
The presence of the ##\sqrt{1 - x^2}## factor suggests that a trig substitution is called for, and that's the direction that davidmoore and tiny-tim are recommending.

BTW, there are no such words in English as "intergral", "intergrate", or "intergration".