How can I solve simultaneous trigonometric equations involving cosine and sine?

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The discussion focuses on solving simultaneous trigonometric equations involving cosine and sine, specifically the equations 242 = 290cos(theta) + 187cos(phi) and 0 = 290sin(theta) - 187sin(phi). The user has derived that phi + theta = 123.9 degrees but is seeking further assistance. A recommended approach is to express cos(phi) in terms of cos(theta) from the first equation and sin(phi) in terms of sin(theta) from the second equation, then substitute these into the formula for cos(theta + phi) or sin(theta + phi) to reduce the problem to a single variable.

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Joe_I_Am
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How would one go about solving the following equation?

242= 290cos(theta) + 187cos(phi)
0 = 290sin(theta) - 187sin(phi)


I have tried squaring both sides of both equations and adding them, and then using cos2x + sin2x = 1 to narrow some stuff down, and basically only found that:

phi + theta = 123.9 degrees.

But I still feel like I'm stuck. Maybe I'm missing an identity or something, I am terrible with those. Any help would be appreciated.
 
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Just realized I put this in the wrong forum,...sorry guys.
 
Since this is homework, here are some strategy hints

Call your equations above 1,2,3

From 1 get cos\phi in terms of cos\theta

From 2 get sin\phi in terms of sin\theta

substitute into either the formula for

cos (\theta + \phi)

or

sin (\theta + \phi)

Substituting into 3 will get you an equation in a single unknown.
 

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