How can I solve this implicit differentiation problem?

Click For Summary

Discussion Overview

The discussion revolves around solving an implicit differentiation problem, specifically focusing on how to express the derivative dy/dx in terms of y and determining conditions under which dy/dx equals zero. The scope includes mathematical reasoning and clarification of differentiation techniques.

Discussion Character

  • Mathematical reasoning, Homework-related, Conceptual clarification

Main Points Raised

  • One participant presents an implicit differentiation problem and seeks assistance in expressing dy/dx in terms of y.
  • Another participant suggests that for dy/dx to equal zero, the equation x(4y + 2/5y^2) must hold, leading to potential solutions of x=0 or y=-1/√10.
  • A different participant introduces a new example, 1 - 2x/4 + 2y = 0, and seeks clarification on how to find dy/dx for this equation.
  • In response, a participant indicates that along the line y=x/4 - 1/2, dy/dx will equal zero.
  • One participant expresses confusion regarding the steps taken by their lecturer to arrive at a specific value of x=1/2 in their notes.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the methods or steps involved in solving the implicit differentiation problems, as there are multiple approaches and some expressions of uncertainty.

Contextual Notes

There are limitations in the clarity of the steps taken to derive certain values, and assumptions about the conditions under which dy/dx equals zero are not fully explored.

Who May Find This Useful

Students and individuals interested in implicit differentiation, mathematical problem-solving, and those seeking clarification on differentiation techniques may find this discussion relevant.

dankelly08
Messages
15
Reaction score
0
so I have a implicit diffentiation problem and was wondering if someone could help me out.. I need to figure out how to get

dy/dx=0

so eg if i had

dy/dx = 4xy+2x/5y^2

and you want to write this in terms of y, how is this done? is there a trick?
 
Physics news on Phys.org
Well, if dy/dx is to be 0, it follows that:
[tex]x(4y+\frac{2}{5y^{2}})=0[/tex]
Having as possible solutions that either x=0, or [tex]y=-\frac{1}{\sqrt[3]{10}}[/tex]
 
thanks for your help, but I am still not too sure how this works so how about with this example

1-2x/4+2y = 0
 
Well, then along the line y=x/4-1/2, dy/dx will equal zero.
 
ah right thanks, its just I'm trying to figure out in my notes what steps my lecturer took to get x=1/2.. and i can't see how he's done it..
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K