How can I use logarithms to determine the growth rate of a bacteria colony?

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SUMMARY

This discussion focuses on using logarithmic equations to determine the growth rate of a bacteria colony. The user explores two formulas: P = P0at and P = P0ekt, ultimately calculating the time required for the colony to triple in size. Both methods yield similar results, approximately 7.92473 hours and 7.92484 hours, confirming the equivalence of the equations through the relationship a = e^k. The user seeks clarification on which equation is more appropriate for this scenario.

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  • Understanding of logarithmic functions and their properties
  • Familiarity with exponential growth models
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Biologists, mathematicians, and students studying population dynamics or logarithmic functions will benefit from this discussion, particularly those interested in applying mathematical models to biological growth scenarios.

Jacobpm64
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We're on the section of logarithms, so I'm guessing this has something to do with them...

If the size of a bacteria colony doubles in 5 hours, how long will it take for the number of bacteria to triple?

I know that doubling time and all that stuff is independent of the amount of something you have...

Should I use P = P0at or P = P0ekt ?

I'll just try it both ways to show some work, but I don't know which equation i'd be using...

first with P = P0at
2 = 1a5
2 = a5
a = 21/5
a = 1.1487

3 = (1.1487)t
ln3 = tln(1.1487)
t = ln3 / ln1.1487
t = 7.92473 hours


Now, to try using P = P0ekt

2 = 1e5k
2 = e5k
ln2 = 5k
k = ln2 / 5
k = .138629

3 = 1e.138629t
3 = e.138629t
ln3 = .138629t
t = ln3 / .138629
t = 7.92484 hours

very close answers, which one equation should i have used, and is the answer right?
 
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A quick glance should convince you that ##a=e^k##, so the answers are equivalent.
 
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