How can rationalizing the numerator help solve limits algebraically?

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Homework Help Overview

The problem involves evaluating the limit as x approaches 0 of the expression (square root(4+x^4)-2)/x^4 algebraically, with a focus on the technique of rationalizing the numerator.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the rationale behind rationalizing the numerator and its implications, noting that it can introduce a square root in the denominator. There are attempts to clarify the form of the expression after rationalization and questions about the resulting structure of the limit.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the rationalization process. Some guidance has been offered regarding the form of the expression, and there is an acknowledgment of potential misunderstandings in the rationalization steps.

Contextual Notes

There is a mention of previous discussions on the necessity of rationalizing the numerator, indicating that this is a common topic of inquiry. Participants express confusion about the outcomes of their attempts, suggesting that clarity on the steps taken is needed.

famallama
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Homework Statement


Evaluate limit as x approaches 0 of (square root(4+x^4)-2)/x^4) algebraically by rationalizing the numerator. Show details


The Attempt at a Solution


I rationalized the numerator and i see it as there is a root in the denominator now which is when i was taught to rationalize
 
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Some time ago, we had a question on this forum basically asking why you always rationalize the numerator! The answer is, of course, that you don't always- although for many basic algebra problems, such as adding fractions, that helps. I have seen texts that devote quite a lot of time to rationalizing the numerator as well.

Okay,if you have rationalized the numerator, you will have a square root in the denominator- but that doesn't hurt. It should be of the form [itex]\sqrt{4+ x^4}+ 2[/itex] which goes to 4, not 0, as x goes to 2. What happens to the rest of the fraction? That's the important thing!
 
that doesn't really help. I get x^4 -4(sqrt(4+x^4)) +6 on top of x^4(sqrt(4+x^))-2x^4
 
Hi famallama! :smile:

(have a square-root: √ :smile:)
famallama said:
that doesn't really help. I get x^4 -4(sqrt(4+x^4)) +6 on top of x^4(sqrt(4+x^))-2x^4

erm … the object is to have no √ on the top :redface:

Hint: your factors had a - on the top and the bottom … try it with a + :smile:
 
famallama said:
that doesn't really help. I get x^4 -4(sqrt(4+x^4)) +6 on top of x^4(sqrt(4+x^))-2x^4
Well, you shouldn't. Since "rationalizing" the numerator should get rid of the square root in the numerator, it appears you haven't done that properly. If you would show your work we might be able to clarify things.
 

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