How Can the Derivative of y=3x²ln(x) Be Simplified Further?

  • #1
anthonyk2013
125
0
y=3x2Inx

u=3x2
v=Inx
du/dx=6x
dv/dx=I/x

y=u*v

dy/dx=(u)(dv/dx)+(v)(du/dx)

dy/dx=(3x2)(I/x)+(Inx)(6x)

Can I simplify this further
 
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  • #2
anthonyk2013 said:
y=3x2Inx
What is Inx? If you are going by what is on a button on a calculator, that is ln x (LN), for natural logarithm.
anthonyk2013 said:
u=3x2
v=Inx
du/dx=6x
dv/dx=I/x
If v = ln(x), then dv/dx = 1/x, not I/x.
anthonyk2013 said:
y=u*v

dy/dx=(u)(dv/dx)+(v)(du/dx)

dy/dx=(3x2)(I/x)+(Inx)(6x)

Can I simplify this further

Please post homework-type problems in the Homework & Coursework section, not in the technical math sections. I am moving this thread.
 
  • #3
Mark44 said:
What is Inx? If you are going by what is on a button on a calculator, that is ln x (LN), for natural logarithm.
If v = ln(x), then dv/dx = 1/x, not I/x.


Please post homework-type problems in the Homework & Coursework section, not in the technical math sections. I am moving this thread.

It's not homework!
 
  • #4
But it's a homework-type problem, so this is where it goes.
 
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