How can the observer's speed make events A and B simultaneous?

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Homework Help Overview

The problem involves determining the speed at which an observer must move along the +x-axis for two events, A and B, to be perceived as simultaneous. The context is rooted in the principles of relativity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulation of the problem, with one suggesting the use of β=v/c for simplification. Questions arise regarding the interpretation of multiple solutions and the validity of derived equations.

Discussion Status

The discussion is active, with participants exploring different approaches to solving the equation. Some guidance has been offered regarding the use of quadratic equations, but there is no consensus on which solution is correct given the presence of multiple values.

Contextual Notes

Participants note potential issues with spurious solutions arising from squaring equations, and there is an acknowledgment of constraints related to the direction of velocity and the nature of the solutions derived.

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Homework Statement


How fast must the observer be moving in the +x-axis direction so that events A and B occur simultaneously?

Homework Equations


I am currently in the solving stage of this problem and I need some help factoring this out/entering it into Octave. Can anyone help?


The Attempt at a Solution


I am currently nearing the end of the (*hopefully) working solution. I am currently here:

1.296e33=v^2(9e16-v^2)

How do I solve from here either by hand, or by entering it into MATLAB/Octave? I appreciate all help! Thank you very much for your time.
 
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In relativity, it's generally better to solve for β=v/c rather than v alone. It just keeps things neater. In your case, if you divide by c4, you'll get

[tex]\beta^2(1-\beta^2) = 0.16[/tex]

This is a quadratic in β2. Solve for β2 by factoring, if possible, or by using the quadratic equation.
 
Thank you for your reply. However, by entering that function into my calculator, I find that the function has 4 zeros. Even if I assume that the velocity cannot be negative (because we're moving in the +x direction), I still have two values that are directly proportional by a factor of 2. How do I determine which one it is? The values end up being 0.447214c and 0.89443c FYI. Thanks.
 
I can't say as I don't know how you got that equation. I'm guessing to get to that point you squared another equation, which introduced a spurious solution. If that's the case, you just have to try both solutions in the original equation and see which one works.
 
I found the zeros to the equation you gave me above...
 

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