How Can the Refractive Index Be Less Than One?

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The Lorentz model indicates that the refractive index can be less than one when the frequency exceeds the resonance frequency, leading to phase velocities that exceed the speed of light. This phenomenon does not violate the principle that nothing can travel faster than light in a vacuum, as no information or energy is transmitted at these speeds. Historical discussions by Sommerfeld and Brillouin clarify that in regions of anomalous dispersion, the group velocity does not represent a valid signal-propagation speed due to significant signal deformation. The wavefront velocity remains equal to the speed of light in a vacuum, ensuring compliance with relativity. Thus, the apparent contradiction is resolved within the framework of classical electrodynamics.
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Homework Statement
The Lorentz model to calculate the refraction index of a dielectric, in the simplest of terms states the following equation: (see relevant equations)
Relevant Equations
##n^2(\omega) = 1 + \frac {\omega^2_p} {\omega^2_0 - \omega^2}##
Hello fellow users,

I've been given the Lorentz model to calculate the refraction index of a dielectric, the formula in its simplest way states that:
##n^2(\omega) = 1 + \frac {\omega^2_p} {\omega^2_0 - \omega^2}##

Where ##\omega_p## is the plasma frequency and ##\omega_0## is the resonance frequency.

If ##\omega > \omega_0## the refraction index ##n## can be smaller than 1 and experimental results verify this. How does this result reconcile with the fact that "nothing can travel faster than light in a vacuum"?

I need to make a bibliographical search and give an explanation for this, but I can't find an exact answer to this question or the same formula I'm given.
I need your help please! Thank you in advance!
 
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I think it is just that the phase velocity is faster than light; no energy is being propagated at that speed.
 
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tech99 said:
I think it is just that the phase velocity is faster than light; no energy is being propagated at that speed.
 
This is a very old apparent problem. It was asked Sommerfeld by Willy Wien in 1907, and Sommerfeld wrote a very short article showing by using a complex integral and the theorem of residues that there's nothing violating Einstein causality and that there's nothing propagating faster than the speed of light that is not supposed to do so in the region of anomalous dispersion. The details have been worked out by Sommerfeld and Brillouin in two papers in the Annalen der Physik in 1914.

You find a summary in Sommerfeld's Lectures on Theoretical Physics vol. 4 (Optics) as well as in Jackson's Classical electrodynamics. The upshot is that in the frequency realm around the resonance group velocity doesn't make sense as an approximate signal-propagation velocity as it does in regions of "normal dispersion", because the transient signal is deformed so much that you cannot consider it a smoothly moving wave packet. In this model the front velocity of the wave is exactly ##c_{\text{vac}}##, and thus there's no signal which propagates faster than light, and everything is in accordance with relativity as you expect from Maxwell's equations, which is the paradigmatic example of a classical relativistic field theory :-).
 
So is there some elegant way to do this or am I just supposed to follow my nose and sub the Taylor expansions for terms in the two boost matrices under the assumption ##v,w\ll 1##, then do three ugly matrix multiplications and get some horrifying kludge for ##R## and show that the product of ##R## and its transpose is the identity matrix with det(R)=1? Without loss of generality I made ##\mathbf{v}## point along the x-axis and since ##\mathbf{v}\cdot\mathbf{w} = 0## I set ##w_1 = 0## to...

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