Dispersion Relations and Refractive INdex

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SUMMARY

The discussion focuses on proving the refractive index and attenuation length in plasma physics. The refractive index is defined as n = √(1 - (ω/ωₚ)²), where ωₚ = √(Ne²/(mε₀)). The attenuation length is given by L = (c/ω) √(1/((ωₚ/ω)² - 1)). Participants clarify the relationship between the refractive index and dispersion relations, emphasizing the importance of the conductivity formula σ = i(Ne²/(mω)).

PREREQUISITES
  • Understanding of plasma conductivity, specifically σ = i(Ne²/(mω))
  • Familiarity with refractive index calculations in plasma physics
  • Knowledge of the dispersion relation k² = μεω² + iμσω
  • Basic concepts of electromagnetic wave propagation in materials
NEXT STEPS
  • Study the derivation of the plasma frequency ωₚ = √(Ne²/(mε₀))
  • Explore the relationship between the imaginary part of permittivity and attenuation length
  • Learn about the exponential decay of electromagnetic radiation intensity in materials
  • Investigate advanced topics in dispersion relations in plasma physics
USEFUL FOR

Students and researchers in plasma physics, electrical engineering, and materials science who are working on electromagnetic wave propagation and its interactions with plasma.

tomeatworld
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Homework Statement


The conductivity of a plasma is defined as \sigma = i\frac{Ne^{2}}{m\omega} where N is the electron density.

a) Prove the refractive index is: n = \sqrt{1- (\frac{\omega}{\omega_{p}})^{2}} with \omega_{p} = \sqrt{\frac{Ne^{2}}{m\epsilon_{0}}}

b) Show the Attenuation length is L = \frac{c}{\omega} \sqrt{\frac{1}{(\omega_{p}/\omega)^{2}-1}}


Homework Equations


k^{2} = \mu\epsilon\omega^{2} + i\mu\sigma\omega


The Attempt at a Solution


I can't find equations linking the refractive index to the dispersion relation. Also, don't know anything about the attenuation length.

Can I grab a push in the right direction?
Thanks

Edit: Right, for the first part, I stumbled upon the equation n^{2} = \frac{c^{2}}{\omega^{2}} k^{2} but I get an answer inverse to the required answer, with an extra factor of c^{2}. Can someone just verify I've almost got there or that that equation is completely wrong. Thanks.
 
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tomeatworld said:

Homework Statement


The conductivity of a plasma is defined as \sigma = i\frac{Ne^{2}}{m\omega} where N is the electron density.

a) Prove the refractive index is: n = \sqrt{1- (\frac{\omega}{\omega_{p}})^{2}} with \omega_{p} = \sqrt{\frac{Ne^{2}}{m\epsilon_{0}}}

b) Show the Attenuation length is L = \frac{c}{\omega} \sqrt{\frac{1}{(\omega_{p}/\omega)^{2}-1}}

Homework Equations


k^{2} = \mu\epsilon\omega^{2} + i\mu\sigma\omega

The Attempt at a Solution


I can't find equations linking the refractive index to the dispersion relation. Also, don't know anything about the attenuation length.

Can I grab a push in the right direction?
Thanks

Edit: Right, for the first part, I stumbled upon the equation n^{2} = \frac{c^{2}}{\omega^{2}} k^{2} but I get an answer inverse to the required answer, with an extra factor of c^{2}. Can someone just verify I've almost got there or that that equation is completely wrong. Thanks.
I think you're right, and what you are being asked to prove is slightly wrong. It should be
n = \sqrt{1 - \biggl(\frac{\omega_p}{\omega}\biggr)^2}
according to e.g. http://farside.ph.utexas.edu/teaching/em/lectures/node98.html (By the way, that's a good read)

As for the attenuation length: the intensity of EM radiation inside a material decreases exponentially as a function of the distance penetrated into the material. Mathematically,
I \propto e^{-x/\lambda}
The constant \lambda is the attenuation length. It's related to the imaginary part of the permittivity \epsilon (and also related to the dispersion relation). Check your notes or references and see whether that helps you find anything relevant.
 

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