First of all, these are all wonderful questions. And, I guarantee, we all asked these questions too.
QUESTION 1
Ball comes and hits the bat.
Mass of the ball=m
Mass of the bat=M
Force exerted by ball= ƒ
Force exerted by the bat=F
Every action as equal and opposite reaction (---1---) . P.S. {here action word is used instead of the word "force" , its more than what meets the eye}.
ƒ=F right? (Since, ---1--- is correct).
But if that's so, the ball should stay there only. How does it move when we hit it?
What actually moves the ball is acceleration, not force. Let's say the bat's mass is 5kg, and the ball's mass is .25kg, and the force induced from the bat to the ball is 25N.
$$
F_{bat->ball} = 25N
$$
$$
F_{ball->bat} = -25N
$$
By Newton's second law, ##F=ma## :
$$
F_{ball} = m_{ball}a_{ball}
$$
$$
F_{bat} = m_{bat}a_{bat}
$$
We solve this for the acceleration of the ball and bat:
$$
a_{ball} = \frac{F_{ball}}{m_{ball}}
$$
$$
a_{bat} = \frac{F_{bat}}{m_{bat}}
$$
We know the forces involved, and we know the masses, so we can find the acceleration:
$$
a_{ball} = \frac{25}{.25} = 100 \frac{m}{s^2}\
$$
$$
a_{bat} = \frac{-25}{5} = -5 \frac{m}{s^2}
$$
So, you see, the motion of each object is different, even though the force is the same, because they have different masses.
QUESTION 2
Also, Our Earth and us. Earth applies force on us , so we are applying equal and opposite force to it. If that's so, then why are we attracted towards it? Why don't we just fly in the air because we apply equal force on it always.
This is the same question as question 1.
My mass is 59kg. To find the force of gravity between me and the Earth, we use the equation I used above:
$$
F_g = -mg
$$
$$
F_g = -(59)(9.81) = -578.79 N
$$
Now, because of Newton's third law, we know that the force I exert on the Earth is 578.79N... Note the missing negative sign: The force is equal, but opposite.
Now, using Newton's second law, we can calculate the gravitational acceleration me and the Earth end up getting.
$$
a_{me} = \frac{-578.79}{59} = -9.81 \frac{m}{s^2}\
$$
$$
a_{Earth} = \frac{578.79}{5972198600000000000000000} = .00000000000000000000009691 \frac{m}{s^2}
$$
That's small.
QUESTION 3
If we are on Earth, we will experience other planet's gravitation too right? So if we are on space, aren't we supposed to be attracted towards sun and fall for it?
The International Space Station is 407120 meters above the surface of the Earth. The Earth's radius is 6367444 meters. The distance the ISS has from the center of the Earth is the sum of these two values, which is 6774564 meters.
The mass of the Earth is of course 5972198600000000000000000 kg.
The universal gravitational constant, G, is .0000000000667.
We can use these numbers with Newton's law of universal gravitation, which I defined earlier:
$$
F_g = G\frac{M_{ISS}M_{Earth}}{d^2}
$$
Since we only care about the ISS's acceleration of gravity, we can factor out the mass of the ISS itself.
$$
a_g = -G\frac{M_{Earth}}{d^2} = -(.0000000000667)\frac{5972198600000000000000000}{6774564^2} = -8.68 \frac{m}{s^2}
$$
That's not anywhere close to zero. In fact, it seems the astronauts are still quite affected by Earth's gravity. It seems paradoxical. For an intuitive understanding, I invite you to play Kerbal Space Program. =^)
QUESTION 4
{Okay this question is bit out of the topic} , Our Earth moves very fast, but why don't we experience such a fast motion??
You're also going very fast on an airplane, or on a highway, and you don't experience that fast motion, do you? It's Newton's first law: Whatever is in motion, stays in motion. Inertia.
We can only "experience" acceleration, in the way you describe. Indeed, when you speed up in a car, or lift off in an airplane, you're pushed to the back of you seat.
And of course, we do "experience" the gravitational and rotational acceleration of the Earth in the form of the tides and the precession of the Foucault pendulum.