How can water pressure be measured in m

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Discussion Overview

The discussion focuses on how to measure water pressure in meters, particularly in the context of minimum residual pressure in water distribution systems. Participants explore the concept of pressure head and its relationship to fluid dynamics, while also considering practical applications in civil engineering and waterworks education.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • One participant seeks clarification on measuring minimum residual pressure in meters, referencing a specific design criterion in South African civil engineering.
  • Another participant explains that pressure can be expressed in terms of 'head', indicating that a 24m head corresponds to the pressure exerted by a column of water 24m high.
  • There is a discussion about whether a head of 10m is considered low pressure and a head of 50m high pressure, with questions about the effect of pipe diameter on pressure.
  • Participants discuss the conversion between different pressure units, including pascals and pounds per square inch, while noting that various units are still in common usage.
  • A participant provides a derivation of pressure based on the height of a water column, emphasizing that pressure is independent of the area of the column, thus the diameter of the pipe does not affect the pressure head.

Areas of Agreement / Disagreement

Participants express various viewpoints on the relationship between pressure head and pipe diameter, with some clarifying that diameter does not influence pressure head. However, there is no consensus on the implications of different pressure levels (low vs. high) or the best way to explain these concepts.

Contextual Notes

Limitations include potential misunderstandings regarding the use of pressure head to describe standalone pressure versus differences in pressure, and the assumptions made about the constancy of density and gravitational acceleration in specific cases.

Who May Find This Useful

This discussion may be useful for civil engineers, educators in waterworks, and students studying fluid dynamics or related fields.

dacgray
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How can water pressure be measured in "m"

Hi

I need to understand how minimum residual pressure can be measured in meters. At least I think its meters. The specific sentence in the abstract is:

"The South African civil engineering fraternity has grown to accept 24 m as the design criterion for minimum residual pressure in water distribution systems. However, the theoretical peak demand in many systems has increased beyond the point where minimum residual pressure exceeds 24 m – at least according to hydraulic models."

A copy of this paper can be found at
http://www.scielo.org.za/scielo.php?pid=S1816-79502009000200007&script=sci_arttext

I am developing material to help the South African waterworks department teach its staff along the lines of South African unit standard 254073, and while I am a skilled materials developer, I do not have a background in fluid dynamics. (It's South Africa)

Any help would be much appreciated.
 
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You can express pressure in 'head'.
http://en.wikipedia.org/wiki/Pressure_head

Ie the desgin pressure is that made by a column of water 24m high. Or the difference between atmospheric (for example) and another perssure is 24m.
 


Thanks for the reply,

So would a way that I could explain it be that if the 'head' in a water pipe is 24m, that pressure would be enough to push that water 24m up at normal g? Could I say that a head of 10 m is low pressure, and a head of 50m is high pressure.

another way that I could say it would be that a 24m high column of water would push down with 24m head of pressure. What effect would the diameter of the pipe have on this pressure?

Is there a way that I can convert between head, pascal and pounds per square inch?

Much appreciated.
 


While Pa is the SI unit for pressure there are various different units still in common usage. Below are a few of the most common ones and their corresponding relation to the standard atmosphere.

1 atm (Atmosphere) = 1.013E5 Pa = 1.013 Bar = 14.7 psi = 10.3m water = 760 mm Hg

* some of the above are approximate.
 


dacgray said:
Thanks for the reply,

So would a way that I could explain it be that if the 'head' in a water pipe is 24m, that pressure would be enough to push that water 24m up at normal g? Could I say that a head of 10 m is low pressure, and a head of 50m is high pressure.

another way that I could say it would be that a 24m high column of water would push down with 24m head of pressure. What effect would the diameter of the pipe have on this pressure?

Is there a way that I can convert between head, pascal and pounds per square inch?

Much appreciated.

You don't use pressure head to describe a stand alone pressure (its more convenient to simply use a pressure), it's used to describe a difference in pressure. This usualyl comes from experimental values.

As such diameter of the pipe would have no effect on the head. It simply says the difference between the two pressures is enough to send water up a colum 24m.

Just like is a swimming pool, if you have a 25m long pool the pressure at a given depth is the same as if you were in a 50m olympic pool.
 
Last edited:


Imagine a column of water of a given height h and of area A. What is the pressure P felt under that column?

So:

P = W / A where W is the weight of the column of water.

And:

W = m g where m is the mass of water and g is the acceleration of gravity.

m = rho V where rho is the density of water and V the volume of water.

V = A h

Putting everything together:

P = (m g) / A = (rho V g) / A

P = rho g h

Since rho and g can be assume constant for some specific cases, the pressure varies only with the height of the column of water, no matter what is the area of the column (hence the diameter of the pipe). This is how we can measure pressure in meter. This case was for water, but if you use the density of mercury (Hg) instead, you could measure in "mm Hg", i.e. "equivalent pressure felt under a column of mercury with a height of X millimeters".

The same logic applies to air pressure. If we feel a 101 kpa of air pressure on the ground, it is because of the weight of the air over our head that is pushing down on us due to gravity. (Although, in this particular case, rho and g will vary with height)
 


Thank you for your help
 

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