How can we compute expectation values for spin states using Pauli matrices?

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To compute expectation values for spin states using Pauli matrices, the expression for the expectation value of the spin operators can be simplified using the orthogonality of the states involved. Specifically, the calculation of ##\langle +z|\hat{\mathbb{S}}_++\hat{\mathbb{S}}_-|+z\rangle## results in zero due to the orthogonality of the states ##|+z\rangle## and ##|-z\rangle##. A pedagogical approach involves representing the spin states as vectors and using matrix multiplication with the Pauli matrices. For instance, defining ##|+z\rangle = (1,0)^{T}## and ##|-z\rangle = (0,1)^{T}## allows for straightforward calculations of expectation values. This method is particularly effective for spin-1/2 systems, while higher spins may complicate the process.
Robben
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Homework Statement



When calculating expectation values for spin states I encountered ##\langle \hat{\mathbb{S}}_+\rangle = \langle+z|\hat{\mathbb{S}}_+|+z\rangle = \frac12\langle+z|\hat{\mathbb{S}}_++\hat{\mathbb{S}}_-|+z\rangle.##

How do we compute ##\langle+z|\hat{\mathbb{S}}_++\hat{\mathbb{S}}_-|+z\rangle?##

Also, similary ##\langle+z|\left(\hat{\mathbb{S}}_++\hat{\mathbb{S}}_-\right)^2|+z\rangle?##

Homework Equations



##\hat{\mathbb{S}}_x=\frac12(\hat{\mathbb{S}}_++\hat{\mathbb{S}}_-)##

The Attempt at a Solution



I know that ##\langle+z|\hat{\mathbb{S}}_++\hat{\mathbb{S}}_-|+z\rangle = 0## but I am not sure how to compute it to get zero.

Do I compute ##\left(\hat{\mathbb{S}}_++\hat{\mathbb{S}}_-|+z\rangle\right)## first, which gives ##\hbar|-z\rangle## and then use the bra ##\langle +z|## to get zero?

 
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One approach, which I think is very pedagogic, is to write everything in terms of vectors and matrices. This can be done in this case because a spin has a finite length, while it would be more difficult for the case of a harmonic oscillator.

For example you can define ##\vert +z \rangle = (1,0)^{T}##, ##\vert -z \rangle = (0,1)^{T}##.
Then you have to express the spin operator in terms of Pauli matrices, and multiply everything.

e.g. ##\langle +z \vert S_z \vert +z \rangle = (1,0) \dfrac{\hbar}{2}\sigma_z (1,0)^{T} = \dfrac{\hbar}{2}##

P.S. note that if your spin is not ##1/2## then it might be tough...
 
Robben said:

Homework Statement


Do I compute ##\left(\hat{\mathbb{S}}_++\hat{\mathbb{S}}_-|+z\rangle\right)## first, which gives ##\hbar|-z\rangle## and then use the bra ##\langle +z|## to get zero?

This is the rigorous way, yes. You get zero because the states ##\vert +z\rangle## and ##\vert -z\rangle## are orthogonal.
 
matteo137 said:
One approach, which I think is very pedagogic, is to write everything in terms of vectors and matrices. This can be done in this case because a spin has a finite length, while it would be more difficult for the case of a harmonic oscillator.

For example you can define ##\vert +z \rangle = (1,0)^{T}##, ##\vert -z \rangle = (0,1)^{T}##.
Then you have to express the spin operator in terms of Pauli matrices, and multiply everything.

e.g. ##\langle +z \vert S_z \vert +z \rangle = (1,0) \dfrac{\hbar}{2}\sigma_z (1,0)^{T} = \dfrac{\hbar}{2}##

P.S. note that if your spin is not ##1/2## then it might be tough...

Thank you very much!
 
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