MHB How can we simplify this expression involving square roots?

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The expression $$4\sqrt{n^{2}}+\sqrt{m^{2}n-\sqrt{4n^{2}}}-\sqrt{mn^{2}}$$ can be simplified by recognizing that $\sqrt{n^2} = n$ and $\sqrt{4} = 2$. This leads to the simplification of the first term to $4n$. The discussion emphasizes the importance of using properties of square roots, such as $\sqrt{ab} = \sqrt{a}\cdot\sqrt{b}$. Additionally, it is noted that if $n$ is non-negative, $\sqrt{n^2}$ simplifies directly to $n$, while in general, it should be expressed as $|n|$. Understanding these simplifications is key to tackling the expression effectively.
Zoey323
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$$4\sqrt{n^{2}}+\sqrt{m^{2}n-\sqrt{4n^{2}}}-\sqrt{mn^{2}}$$
I don't even know where to start, I know the teacher said to distribute but distibute what?
 
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Zoey323 said:
$$4\sqrt{n^{2}}+\sqrt{m^{2}n-\sqrt{4n^{2}}}-\sqrt{mn^{2}}$$
I don't even know where to start, I know the teacher said to distribute but distibute what?
Well, you could start by simplifying [math]\sqrt{n^2}[/math]. What is that?

-Dan
 
Zoey323 said:
$$4\sqrt{n^{2}}+\sqrt{m^{2}n-\sqrt{4n^{2}}}-\sqrt{mn^{2}}$$
I don't even know where to start, I know the teacher said to distribute but distibute what?

Not necessarily distribute but observe and simplify.

Use facts like

$\sqrt(n^2) = n$ and facts like $\sqrt(4) = 2$

To start you off, notice,

$4\sqrt(n^2) = 4n$

Also remember facts like

$\sqrt(ab) = \sqrt(a)\cdot\sqrt(b)$
 
If $n$ is known to be non-negative, then we can write:

$$\sqrt{n^2}=n$$

Otherwise, we should write by definition:

$$\sqrt{n^2}=|n|$$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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