How Can You Find Functions with Indeterminate Limits at Infinity?

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To find functions f and g that approach zero as x approaches infinity, while ensuring that the limit of their ratio approaches positive infinity, f must decrease to zero slower than g. A suggested approach is to define f(x) as 1/F(x) and g(x) as 1/G(x), where F(x) grows to infinity at a slower rate than G(x). This ensures that the limit of f(x)/g(x) results in a form that approaches infinity. The key is to select functions where g(x) approaches zero significantly faster than f(x). Understanding this relationship is crucial for solving indeterminate limits at infinity.
LemuelUhuru
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Hi, I am in a first semester Calculus I course in college with an intermediate skill level with precalc and a basic understanding of limits and infinity. I do not understand how to solve this problem I attempted to do so only to find out after completion that ∞/∞ is indeterminate rendering my solution void.

Homework Statement



Suppose f(x) →0 and g(x) → 0 as x → +∞. Find examples of functions f and g with these properties and such that:
a. limx→+∞\left[\frac{f(x)}{g(x)}\right] = + ∞

The Attempt at a Solution



Here is my attempt

Let f(x) = 1/x and g(x) = (1/x)+1
limx→+∞ \left[\frac{\frac{1}{x}}{\frac{1}{x}+1}\right]= \frac{1}{x} * \frac{x}{1}+1 = ∞ + 1 = + ∞
 
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LemuelUhuru said:
Hi, I am in a first semester Calculus I course in college with an intermediate skill level with precalc and a basic understanding of limits and infinity. I do not understand how to solve this problem I attempted to do so only to find out after completion that ∞/∞ is indeterminate rendering my solution void.

Homework Statement



Suppose f(x) →0 and g(x) → 0 as x → +∞. Find examples of functions f and g with these properties and such that:
a. limx→+∞\left[\frac{f(x)}{g(x)}\right] = + ∞

The Attempt at a Solution



Here is my attempt

Let f(x) = 1/x and g(x) = (1/x)+1
First problem, g(x) doesn't go to 0 in the limit as ##x \to \infty##.

limx→+∞\left[\frac{\frac{1}{x}}{\frac{1}{\frac{1}{x}+1}}\right] = \frac{1}{x} * \frac{x}{1}+1 = ∞ + 1 = + ∞
I'm not sure what you did here because you have f(x) in the numerator but 1/g(x) in the denominator, and then you did some funky "algebra."
 
Hi Vela,

I realize now that g(x) doesn't go to zero, that was a huge error and I adjusted the original attempt with respect to 1/g(x), although that despite it being irrelevant now, however, I am still unsure how to approach this problem generally. I imagine that I am suppose to obtain to two functions both f(x) and g(x) who limit approaches zero and when divided result in a/0 to give me positive infinity?

Thank you,

Lemuel
 
Yup, that's the idea.
 
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I understand, however, right now I'm simply guessing what rational expressions would allow me to do this, is there a more systematic approach to solving this kind of problem?

Also, it seems difficult to obtain a/0 since the limit of f(x) and g(x) as x approaches infinity is zero and any two functions where a/∞ cancels out my constant when x is subtituted for infinity.
 
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All you're looking for is for g(x) to be something that goes to zero really fast, and f(x) to be something that goes to zero slower.

If you're not sure how to do that, make f(x) = 1/F(x) and g(x) = 1/G(x) where F(x) and G(x) go to infinity, but G(x) much faster.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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