How Can You Find Infinite Solutions for a System of Linear Equations?

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SUMMARY

The discussion focuses on finding infinite solutions for a system of linear equations, specifically the equations x - 2y + 3z = 1 and x + 3z = 3. The solution is expressed in parametric form, demonstrating that letting x = λ results in the solution set (x, y, z) = (3, 1, 0) + λ(-3, 0, 1). It is confirmed that the choice of parameter (either x or z) does not affect the solution, allowing for multiple equivalent representations such as (x, y, z) = (3 - 3λ, 1, λ) or (x, y, z) = (3 - z, 1, z).

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unscientific
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Homework Statement



I worked out until the last part of the question and 3 equations with 3 unknowns got reduced to this:

x - 2y + 3z = 1
x + 3z = 3



The Attempt at a Solution




y = 1,
x = 3 -3z

Letting x = λ where λ is any real number,

(x,y,z) = (3,1,0) + λ(-3,0,1)


It wouldn't make a difference if i let z be λ instead right?
 
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The solution you give is the same as [itex]x= 3- 3\lambda[/itex], [itex]y= 1[/itex], and [itex]z= \lambda[/itex]. Since [itex]z= \lambda[/itex], it doesn't matter which you use. You can write the solution as [itex](x, y, z)= (3-\lambda, 1, \lambda)[/itex] or as [itex](x, y, z)= (3-z, 1, z)[/itex].
 

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