How Can You Find the Electric Field E with Given Conditions?

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SUMMARY

The discussion focuses on calculating the electric field E given an electron's initial velocity of (11.0 j + 16.0 k) km/s and a constant acceleration of (2.00 x 1012 m/s2) i, with a magnetic field B of (400 µT) i. The force on the electron is determined using the Lorentz force equation F = q(v x B), resulting in a force of F = 4.88 x 10-28 i N. Subsequently, the electric field is calculated using E = F/q, yielding E = 442 N/C.

PREREQUISITES
  • Understanding of Lorentz force equation F = q(v x B)
  • Knowledge of electric field calculations E = F/q
  • Familiarity with vector operations in physics
  • Basic concepts of electromagnetism
NEXT STEPS
  • Study the effects of magnetic fields on charged particles
  • Learn about the principles of electromagnetism
  • Explore advanced vector calculus in physics
  • Investigate the applications of electric fields in particle physics
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Physics students, electrical engineers, and anyone interested in the dynamics of charged particles in electric and magnetic fields.

Sanjay101
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1. An electron has an initial velocity of (11.0 j + 16.0 k) km/s and a constant acceleration of (2.00 1012 m/s2) i in a region in which uniform electric and magnetic fields are present. If B = (400 µT) i, find the electric field E.
i. j. k2. F=ma
F=qv cross B
3. I tried finding F through one of the ways listed above, and tried using F=Eq equation to get E. However, i got different values for the force and cannot seem to get the answer.
 
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F = qv x B F = 11.0e-31 x (11.0, 16.0, 0) x (4 x 10-6, 0, 0) F = 4.88e-28 i + 0 j + 0 kE = F/q E = 4.88e-28/11.0e-31 E = 4.42 x 10^2 N/C or 442 N/C
 

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