How Can You Further Simplify 2cos2x - 2cosx in Trigonometry?

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Homework Statement


2cos2x-2cosx...how do you simplify this further?


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The Attempt at a Solution


2(cos2x-cosx)..but i have to find 0=2cos2x-2cosx so this doesn't really help me.
 
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would it be pi/2 and 3pi/2?
 
nope...maybe try drawing cos(2x) and cos(x)?
 
[tex]\cos(2x)=2\cos^{2}(x)-1[/tex], so [tex]2\cos(2x)-2\cos(x)=2\cos^{2}(x)-1\cos(x)-1=0[/tex]. Factoring yields [tex](2\cos(x)+1)(\cos(x)-1)=0[/tex]