How Can You Further Simplify 2cos2x - 2cosx in Trigonometry?

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Homework Statement


2cos2x-2cosx...how do you simplify this further?


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The Attempt at a Solution


2(cos2x-cosx)..but i have to find 0=2cos2x-2cosx so this doesn't really help me.
 
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You're trying to find when 2cos(2x)-2cos(x)=0? Start by what you did... you want to find x such that cos(2x)=cos(x). Hint: cosine is periodic
 
[tex]\cos(2x)=2\cos^{2}(x)-1[/tex], so [tex]2\cos(2x)-2\cos(x)=2\cos^{2}(x)-1\cos(x)-1=0[/tex]. Factoring yields [tex](2\cos(x)+1)(\cos(x)-1)=0[/tex]