Whats's the volume under the revolving parabola y=ax(adsbygoogle = window.adsbygoogle || []).push({}); ^{2}. R is x_{max}.

$$V=\int_0^R\pi xdx\cdot y=\pi\int_o^R x\cdot Ax^2dx=\pi A\frac{R^4}{4}$$

Volume should be relative to R^{3}. and if i had, for example, y=Ax^{3}then, according to my calculation i would get relative to R^{7}and so on.

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# Integral (area) of a revolved parabola

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