1. Oct 21, 2013 #1

   Superposed_Cat

   

   http://tutorial.math.lamar.edu/Classes/CalcI/ComputingIndefiniteIntegrals_files/eq0020MP.gif I get how they integrating but I don't get how they simplified the last term.

    

   Superposed_Cat, Oct 21, 2013
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3. Oct 21, 2013 #2

   Mark44

   

   Insights Author

   Staff: Mentor

   Are you stumped by the arithmetic with fractions?
   
   $$ \frac{1}{\frac{7}{4}} = \frac 4 7$$
   Now multiply by 3. What do you get?
   
   6 * 1/2 = ?

    

   Mark44, Oct 21, 2013
4. Oct 21, 2013 #3

   Superposed_Cat

   

   No with this, but my algebra is terrible and I haven't had to use fractions properly for ages as I always usually convert to decimals.

    

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   Superposed_Cat, Oct 21, 2013
5. Oct 21, 2013 #4

   Mark44

   

   Insights Author

   Staff: Mentor

   This isn't even algebra - it's arithmetic, and about 6th grade at that.
   

   Then it would behoove you to brush up on arithmetic involving fractions. Some time spent going through some videos at khanacademy (http://www.khanacademy.org/math/cc-sixth-grade-math) would be a very good investment.

    

   Mark44, Oct 21, 2013
6. Oct 21, 2013 #5

   Astrum

   

   That's just saying that $$\frac{1}{6}\int x^{-1/2}dx = \frac{1}{6}[2x^{1/2}]$$
   
   You're aware of the generic formula: ##\int x^n dx = \frac{1}{n+1}x^{n+1}## right?

    

   Astrum, Oct 21, 2013

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