How Do Absolute Values Affect Solving Function Equations?

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SUMMARY

The discussion focuses on solving function equations involving absolute values, specifically through two examples: g(x) = 3x - 3 + |x + 5| and h(x) = |x| - 3x + 4. For part (a), the equation g(a) = 2a + 8 is solved by isolating the absolute value expression and applying the definition of absolute values based on the sign of the variable. In part (b), the equation h(x - 1) = x - 2 requires substituting x - 1 into h(x) and solving for x. The key takeaway is the importance of understanding how to manipulate absolute values in equations.

PREREQUISITES
  • Understanding of absolute value functions
  • Basic algebraic manipulation skills
  • Familiarity with function notation
  • Knowledge of solving linear equations
NEXT STEPS
  • Study the properties of absolute value functions
  • Learn techniques for isolating variables in equations
  • Practice solving equations involving piecewise functions
  • Explore graphical representations of absolute value equations
USEFUL FOR

Students studying algebra, educators teaching function equations, and anyone looking to improve their problem-solving skills with absolute values in mathematics.

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Homework Statement


I do not see how the two equations in each example are related, what should I do with them? (the l's are absolute value brackets):

a) Let g(x) = 3x - 3 + l x+5 l. Find all values of a which satisfy the equation:

g(a) = 2a +8


b) Let h(x) = l x l - 3x + 4. Find all solutions to the equation :

h(x - 1) = x - 2


I know how to find an equation of the following:

x + l 2x-1 l, find f(x) = 8

x + l 2x-1 l = 8

l 2x-1 l = 8-x

2x-1 = 8-x or -2x+1= 8-x
x=3 x=-7
 
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For part a, you have the formula for g(x), so g(a) = 3a -3 + |a + 3|

Set that expression equal to 2a + 8. Isolate the absolute value expression on one side, and keep in mind that |x| = x if x >= 0 and |x| = -x if x < 0.
 

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