How do bijective holomorphic maps relate on open sets and the unit circle?

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SUMMARY

The discussion centers on the relationship between two bijective holomorphic maps, f and g, defined on an open set A and mapping to the unit circle. It highlights the application of the Riemann Mapping Theorem under the assumption that A is connected and simply connected, allowing for the existence of inverse maps f^{-1} and g^{-1}. The conversation also emphasizes that both f and g are biholomorphic, indicating they are conformal maps that preserve angles. The lack of the connected and simply connected assumption poses a challenge in establishing a direct relationship between f and g.

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Homework Statement


Let f and g be bijective holomorphic maps from an open set A to the unit circle. Let a \in A and c=f(a) and d=g(a). Find a relation between f and g that involves a,c,d,f'(a),g'(a).

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The Attempt at a Solution



If we also assumed that the open set is connected and simply connected, then we could apply the Riemann Mapping Theorem.
If that were the case, then there is a bijective holomorphic map f^{-1}: \text{unit circle} \rightarrow A and g^{-1}: \text{unit circle} \rightarrow A Then by the open mapping theorem, f: A \rightarrow \text{unit circle} is continuous, thus a homeomorphism between A and the unit circle.

I'm not sure where to start because we don't have that "connected and simply connected" assumption.
 
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We also know that f,g are biholomophic which implies that it's a conformal map, thus it is angle preserving. Is this a way to two conformal mapping to each other?
 

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