How Do Electron Transitions in Hydrogen Atoms Produce Photons?

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SUMMARY

The discussion centers on the photon emission from hydrogen atoms during electron transitions. When an electron with 12.1 eV energy collides with a hydrogen atom, it excites the electron from the ground state (n=1, -13.6 eV) to the n=3 state (-1.5 eV). The transitions that occur are 3->2, 2->1, and 3->1, resulting in the emission of three distinct photons with varying energies. The calculation of the wavelength for the photon with the smallest energy is also addressed, utilizing the energy-wavelength relationship defined by E = hc/λ.

PREREQUISITES
  • Understanding of atomic physics, specifically electron energy levels in hydrogen.
  • Familiarity with the concept of photon emission and energy transitions.
  • Knowledge of the energy-wavelength relationship (E = hc/λ).
  • Basic proficiency in significant figures and unit conversions in physics.
NEXT STEPS
  • Calculate the wavelength of photons emitted during electron transitions in hydrogen using E = hc/λ.
  • Explore the concept of energy level diagrams for other elements beyond hydrogen.
  • Study the implications of electron transitions on spectral lines and atomic spectra.
  • Investigate the role of energy quantization in atomic physics and its applications in spectroscopy.
USEFUL FOR

Students studying atomic physics, educators teaching quantum mechanics, and anyone interested in understanding the principles of photon emission and electron transitions in hydrogen atoms.

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Figure 1 shows part of an energy level diagram for a hydrogen atom.

n=4 ------ -0.85eV
n=3 ------ -1.50eV
n=2 ------ -3.40eV
n=1 ------ -13.60eV

When an electron of energy 12.1eV collides with the atom, photons of three different energies are emitted.
[a] on Figure 1 show with arrows the transitions responsible for these photons.

> ?

Calculate the wavelength of the photon with the smallest energy. Give your answer to an appropriate number of significant figures.

>(E = hcl入)
>energy in joules = (??) x 1.6 x 10^-19 = (?)(J)
 
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I think this should be in the homework forum. Someone will probably move it for you. (Whoever does can delete this post)
 
diazona said:
I think this should be in the homework forum. Someone will probably move it for you. (Whoever does can delete this post)

Hi, this is not my homework, I am revising Physics at the moment, I am stuck with this question.
 
I've forgot most of atomic physics. But I can show u the process.
[a]at first n=1,then comes the electron with 12.1eV,so the energy raises from -13.6 to -1.5,and n=3.Energy always wants to go from the high level to the low level,and at this time we have 3 ways,that is 3->2,2->1,3->1,these are the "photons of three different energies"
then is easy
 
mensa said:
I've forgot most of atomic physics. But I can show u the process.
[a]at first n=1,then comes the electron with 12.1eV,so the energy raises from -13.6 to -1.5,and n=3.Energy always wants to go from the high level to the low level,and at this time we have 3 ways,that is 3->2,2->1,3->1,these are the "photons of three different energies"
then is easy


---------------------
---------------------
↓ ...↓
---------------------
↓....↓
---------------------
↓....↓
---------------------

Is it kindda look like this...?:confused:
 
I'm sorry I wasn't here.
But I can't catch your point.
What I said means,at first n=1,after 12.1eV comes,n=3. n=3 has 3 ways to go as following
goto 2,releasing 1.9eV
goto 1,releasing 12.1eV
but after 3 go to 2,we still have a 2,and this 2 can goto 1,releasing 10.2eV
 
Alright, I'm super confused by this point. To the OP: can you upload figure 1? Where are the arrows?
 

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