How do I calculate mass of pulley and force of friction on AtwoodMach.

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To calculate the mass of the pulley and the force of friction in an Atwood machine, data was collected by varying the masses on either side while keeping the total mass constant. The relationship between net force and acceleration was established, leading to a slope that indicates the effective mass of the pulley and the frictional force. The calculated effective mass of the pulley was determined to be 28.5g, with a frictional force of 323.4 dynes. However, discrepancies arose when calculating friction using a different method, suggesting potential errors in the equations or unit conversions. It is crucial to verify the equations and perform dimensional analysis to ensure accuracy in calculations.
francisco300
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Homework Statement


Basically, I need to calculate the mass of the pulley and friction using data that I collected.


Homework Equations


I was given: (m1 - m2)g = (m1 + m2 + mp)a + f


The Attempt at a Solution



For the first part, I collected data using a sensor to find the acceleration. I kept the total mass attached to each cup on each side of the machine constant but changed the difference in their masses by 10g each run.

After 6 runs, I plotted my data of Fnet vs Acceleration. Fnet is (m1 - m2)g (I converted g into dynes). When I get my slope, the lab manual says that i should "expect our plot of (m1 - m2)g vs a to have a slope larger than (m1 - m2)g by an amount equal to the effective mass of the pulley mp and a positive intercept equal to the frictional force f"

My equation turned out to be y = 143.28x + 323.24 (i used best fit line).

This means 143.28 = m1 + m2 + mp
In which case mp= 28.5g right?

Then the force of friction should = 323.4 right?
Is the unit in dynes?


For part b, did the same procedure but kept the net force constant instead of the total mass. I gathered my data and plotted

1/a vs m1 + m2

I got y = 0.0002x + 0.0059 as my best fit line

Now I have to use this equation to find the force of friction

1/a = ((m1 + m2) )/((m1-m2)g-f) + mp/((m1-m2)g-f)


But i get 4950 which I believe is in Netwons and that would be too much considering 323 dynes = 0.00323 Newtons
 

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You seem to be working the equations correctly - they may be the wrong equations of course, so you should check that you understand them. Don't just assume they are right: check!

The first thing you need to do is check those units - do that by dimensional analysis.
 
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