How do I calculate specific work for cooled air with constant pressure?

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SUMMARY

The discussion focuses on calculating specific work for cooled air under constant pressure conditions of 115 kPa. The initial specific volume is 0.06 m3/kg, and the final specific volume is 0.03 m3/kg. The specific work can be determined using the integral formula: Specific Work = ∫12 P dV. The user successfully identifies the equation needed to compute the specific work but seeks clarification on its application.

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Homework Statement



Air is cooled in a process with constant pressure of 115 kPa. Before the process begins, air has a specific volume of 0.06 m^3/kg. The final specific volume is 0.03 m^3/kg. Find the specific work in the process.


Homework Equations



none.


The Attempt at a Solution



I think this equation can be used to solve this:

Specific Work= integral (limit goes from 2 1) PxdV, but I don't understand how do I compute this. There aren't many Specific work related problems online, I've tried searching. Any help or pointers will be greatly appreciated! Thanks!
 
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Specific work is the amount of work done per unit mass of gas.
 
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Thanks, I got it :)
 

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