How do I calculate the area of a square with 490 mm2?

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To calculate the area of a square with an area of 490 mm², one must determine the length of each side, which is found by taking the square root of the area. The square root of 490 mm² is approximately 22.14 mm. The discussion reveals confusion regarding the shape in question, as the provided image may not accurately represent a square. Clarification is needed on the dimensions and shape being analyzed. Ultimately, understanding the basic geometric principles is essential for calculating area correctly.
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Hello!

This is pretty easy but i´m failing...

The area of this "square" should be 490 mm2 .
What the proper way to do this..., I guess its simple geometry but for the moment I am drawing blank...
 

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Something is wrong in your image, when I consider the number all the way at the bottom to be the length of a side... using Pythagoras to calculate the diagonal length doesn't give me the indicated value.
Is it really a square? What precisely measures 22.3?
 
No, its nor really a square. Yes, it was a pretty crappy picture, but I got to the solution on my own. thanks for the help
 
I need help with normal shape area. Anyone?
 
WadeS, welcome to PF :smile:

It would have been best to ask your question in a brand new thread, since it appears unrelated to what was asked here.

That being said, what shape is it you need help with finding the area?:confused:
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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