How do I calculate the forces in a Truss?

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Homework Statement


Truss diagram with a point load P at the top joint, supports at the left and right ends, and spans marked 3m, 3m and 3m along the bottom chord, with the height marked 4m.


Homework Equations


Free-body diagram of a pin-supported truss with top chord, bottom chord and diagonal members labelled A to D and B, with members marked C and loads 2P and P applied at the bottom joints, dimensions 2m high and 1m spacing.


The Attempt at a Solution


I have spent the last 2 hours trying to figure out which part of the truss is compression or tension. Hopefully the second screenshot I took is correct. I tried figuring out the first few parts, just want to make sure that at least I am on the right track.

Handwritten notes on lined paper showing a truss diagram with a triangular frame and member force calculations beneath it, with labels and equations too small to read clearly.
 
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tandennis0703 said:
trying to figure out which part of the truss is compression or tension.
Although it is usually easy to figure out in simple cases, it can be quite tricky. Fortunately, you rarely need to. Just make a stab at it in each case and write the equations accordingly. If the answer comes out negative then you guessed wrong, but so what? You still have the answer.

In fact, in the annotated diagram you put under "relevant equations" you seem to have guessed most wrongly.
And that is not what the "relevant equations" section is for. It's for standard equations that can be applied to a whole class of questions.

In the image of your working, how do you get Cx+Dx=0?
(Please do not post images of your algebra. Take the trouble to type it in. That makes it easier to read and easier to comment on. Images should be for diagrams and textbook extracts.)
 
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Handwritten truss analysis on lined paper showing a small truss diagram with a load arrow at the top, and below it force equations summing forces in the x and y directions, with values for the member forces.


Sorry for the mistakes. I never took statics in my course. I redid everything and used the method of summing the resultant forces in both the x and y direction. I am still a bit confused as to how to figure out whether or not it is a compression/ tension force. Hopefully my calculations are correct.
 
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tandennis0703 said:
Handwritten working on lined paper showing a truss diagram at the top with labelled joints and a force, followed by a series of equilibrium equations written below.


Sorry for the mistakes. I never took statics in my course. I redid everything and used the method of summing the resultant forces in both the x and y direction. I am still a bit confused as to how to figure out whether or not it is a compression/ tension force. Hopefully my calculations are correct.
I did ask you to type in your algebra. I am having trouble reading some of the image, and if I want to comment on an equation I have no easy way to refer to it.
Check the signs in your equations for point B.
 
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haruspex said:
I did ask you to type in your algebra. I am having trouble reading some of the image, and if I want to comment on an equation I have no easy way to refer to it.
Check the signs in your equations for point B.

Joint A:

+^ΣFy=0 ; -2P+(2/3.61)FAB=0
FAB=3.61P

>+ ΣFx=0; -FAE+(3/3.61)(3.61)P=0
FAE=3P

Joint E:


+^ΣFy=0; FEB-P=0
FEB=P

>+ ΣFx=0; 3P - FED=0
FED=3P

Joint B:

+^ΣFy=0; (2/3.61)FBD-P-(2/3.61)(3.61)(P)=0
(2/3.61)FBD=3P
FBD=5.415P

>+ΣFx=0; FBC -(5.415)(3/3.61)(P)-(3.61)(P)(3/3.61)=0
FBC=7.5P

Hence:

stress BC= 7.5P/340 = 250

P=11333N
 
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tandennis0703 said:
Joint B:

+^ΣFy=0; (2/3.61)FBD-P-(2/3.61)(3.61)(P)=0
According to what you calculated at joint A, is AB under compression or
tandennis0703 said:
Joint A:

+^ΣFy=0 ; -2P+(2/3.61)FAB=0
FAB=3.61P

>+ ΣFx=0; -FAE+(3/3.61)(3.61)P=0
FAE=3P

Joint E:


+^ΣFy=0; FEB-P=0
FEB=P

>+ ΣFx=0; 3P - FED=0
FED=3P

Joint B:

+^ΣFy=0; (2/3.61)FBD-P-(2/3.61)(3.61)(P)=0
(2/3.61)FBD=3P
FBD=5.415P

>+ΣFx=0; FBC -(5.415)(3/3.61)(P)-(3.61)(P)(3/3.61)=0
FBC=7.5P

Hence:

stress BC= 7.5P/340 = 250

P=11333N
Now I can read it, it all looks right.
 
haruspex said:
According to what you calculated at joint A, is AB under compression or

Now I can read it, it all looks right.

Thanks for the reply. However I am still a bit confused as to how I know whether or not a bar is undergoing compression or tension. Do I need my calculations in order to figure that out?
 
tandennis0703 said:
Thanks for the reply. However I am still a bit confused as to how I know whether or not a bar is undergoing compression or tension. Do I need my calculations in order to figure that out?
In general, yes. As I posted, it is not always possible to figure it out by simple inspection.