How Do I Calculate the Rebound Heights of a Dropped Golf Ball?

  • Thread starter Thread starter manal950
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating the rebound heights of a golf ball dropped from a height of 10 meters onto a fixed steel plate, utilizing a coefficient of restitution of 0.894. The key equations involved include the initial velocity equation \( u_1 = \sqrt{2gh} \) and the rebound height formula \( h = e^2 \times H \), where \( H \) is the initial height. The step-by-step explanation clarifies how to derive the rebound heights for the first, second, and third bounces using the coefficient of restitution.

PREREQUISITES
  • Understanding of basic physics concepts such as gravitational potential energy and kinetic energy.
  • Familiarity with the coefficient of restitution and its application in collision scenarios.
  • Knowledge of kinematic equations, specifically \( V^2 - u^2 = 2gh \).
  • Ability to perform calculations involving square roots and basic algebra.
NEXT STEPS
  • Study the derivation of the coefficient of restitution and its implications in elastic and inelastic collisions.
  • Learn about energy conservation principles in physics, particularly in free-fall scenarios.
  • Explore advanced kinematic equations and their applications in real-world physics problems.
  • Investigate the effects of different surfaces on the coefficient of restitution and rebound heights.
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of collisions and rebound effects in sports physics.

manal950
Messages
177
Reaction score
0
Hi all

A golf ball is dropped from a height of 10 m on a fixed steel plate. The coefficient of restitution is 0.894 . Find the height to which the ball rebounds on the fist ,second and third bounces ?

this solving for teacher I don't understand clearly can please explain step by step

u1 =root(2gh)
velocity of plate before and after impact
u2= v2 = 0
e(u1 - u2 ) =V2-V1
e(root(2gh) - 0 ) = ( 0 - V1)
V1 = -e X root(2gh)
V^2 - u^2 = 2gh now u = zero
so
V1 = 2gh1
h1 = vb^2/2g
h1 = e^22gh/2g
h = e^2 X H (from this can find each height )

Now I want from you explain the solving In fact I don't understand the solving of my teacher
 
Physics news on Phys.org
Which part that you do not understand?
 
acuuly all parts I don't understand

why u = =root(2gh) why not zero

from where this equation V^2 - u^2 = 2gh

please can explain to me step by step
 

Similar threads

Two balls, dropped with a delay of ##\Delta t##, meet after rebound
  • · Replies 34 ·
2
Replies
34
Views
2K
Find the height of a lamp based on the velocities of projectiles
  • · Replies 40 ·
2
Replies
40
Views
3K
Solving the Stacked Ball Drop Homework
  • · Replies 2 ·
Replies
2
Views
5K
Calculating Rebound Height for a Ball Colliding with Steel Plate
  • · Replies 6 ·
Replies
6
Views
2K
Maximum range on ground for an elevated cannon
  • · Replies 21 ·
Replies
21
Views
4K
Projectile Motion: golf ball velocity to reach the green
  • · Replies 11 ·
Replies
11
Views
4K
Calculating Time and Speed of Rebounds with Coefficient of Restitution
  • · Replies 1 ·
Replies
1
Views
2K
Finding the Ratio and Height of a Double Ball Drop Collision
  • · Replies 2 ·
Replies
2
Views
2K
Ball dropped out a truck window, find bounce height and dist
  • · Replies 4 ·
Replies
4
Views
2K
How Do You Calculate the Motion of a Baseball Thrown Upwards?
  • · Replies 3 ·
Replies
3
Views
2K