How Do I Calculate the Value of g for a Pendulum?

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SUMMARY

The discussion focuses on calculating the gravitational acceleration (g) for a pendulum using the formula T = 2π√(l/g). The user has plotted T² against the length (l) and obtained a gradient of 16. They initially calculated g using the rearranged formula g = l / (T² / 2π²), which resulted in an implausibly small value. The community suggests verifying the algebra, particularly ensuring that the factor of 2 is correctly squared in the calculations.

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  • Understanding of pendulum physics and the relationship between period and length
  • Familiarity with algebraic manipulation and rearranging equations
  • Knowledge of graphing techniques for plotting T² against length
  • Basic grasp of the concept of gravitational acceleration
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  • Review the derivation of the pendulum period formula T = 2π√(l/g)
  • Practice algebraic rearrangement of equations to isolate variables
  • Learn how to accurately interpret the gradient of a graph in physics experiments
  • Explore common pitfalls in calculations involving gravitational acceleration
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Students studying physics, particularly those focusing on mechanics and pendulum motion, as well as educators looking to clarify concepts related to gravitational acceleration and algebraic manipulation.

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Homework Statement



I need to work out g for a pendulum. I have values for length (l) and time (T^2)

Homework Equations



T= 2 pi sqroot (l/g)

The Attempt at a Solution



I have plotted a graph of T^2 against l found the gradient of the line is this the value for g or if not do I need to rearrange the equation making g the subject ?

I am not too strong on algerbra and I came up with g = l / (T^2 / 2 pi^2)

but this gives me a silly small amount for g.

the gradient of my graph is 16 which is also a little high for g?
 
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Double check your algebra...did you forget to square the 2 factor also? I think so, see if your answer makes sense then... hope that helps.
 

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