How Do I Complete This Lewis Structure?

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Discussion Overview

The discussion revolves around drawing the Lewis Dot Structure for the ClF4+ ion, focusing on the challenges of accommodating additional electrons while adhering to or deviating from the octet rule. Participants explore the implications of using higher-energy orbitals and the role of atomic period in determining electron distribution.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant calculated a total of 34 electrons for the Lewis structure of ClF4+, considering the contributions from chlorine and fluorine atoms and the positive charge.
  • Another participant suggested that the lone pair should be placed on the chlorine atom, indicating that the octet rule may not apply due to the involvement of higher-energy orbitals.
  • There is a discussion about whether chlorine, being in the third period, can utilize d orbitals to accommodate extra electrons, with one participant affirming this possibility.
  • One participant questioned if there are general rules for distributing extra electrons to atoms capable of supporting d orbitals, particularly for elements in period 3 or higher.
  • A later reply cautioned against the existence of "hard & fast rules" for Lewis structures, emphasizing that they are simplifications and that quantum chemistry provides a deeper understanding of molecular structures.
  • Symmetry was mentioned as a potential guide for determining electron distribution, with concerns raised about the implications of allowing fluorine atoms to gain extra electrons leading to complex resonance structures.

Areas of Agreement / Disagreement

Participants express differing views on the application of the octet rule and the use of d orbitals in Lewis structures. There is no consensus on a definitive rule for handling extra electrons in such scenarios.

Contextual Notes

Limitations include the simplifications inherent in Lewis diagrams and the need for a more nuanced understanding through quantum chemistry to fully grasp molecular structures.

JeweliaHeart
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Homework Statement


Draw the best Lewis Dot Structures the following species:
ClF4+

Homework Equations



none

The Attempt at a Solution



I calculated that there should be a total of 34 e- in the Lewis structure":
7 (1 chlorine atom) + 28 ( 7 from each of the four fluorine atoms) - 1(b/c the atom has a plus one charge)= 34 e-

My Lewis structure (what I have in it so far) is in the attachment below. I don't know how to add in the two other electrons w/o violating the octet rule or even where they should go if I did add them.
 

Attachments

  • ClF4plus.png
    ClF4plus.png
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The lone pair sits on the chlorine atom. You have to invoke higher-energy orbitals, so the octet rule is not followed.
 
Well, thank you.

And this must be possible b/c the chlorine atom is the third period so it can utilize d orbitals, right?

If so, that makes perfect sense to me, but just for future reference is there some hard & fast rule to apply whenever one comes across problems like these: For example, the extra electrons always goes to the atom that can support d orbitals (i.e. period 3 or higher elements)?
 
JeweliaHeart said:
And this must be possible b/c the chlorine atom is the third period so it can utilize d orbitals, right?
Right. I should've specified that when I said "higher-energy orbitals", it will only be stable if the difference in energy is not to big, and therefore the orbitals must come from the same shell.

JeweliaHeart said:
If so, that makes perfect sense to me, but just for future reference is there some hard & fast rule to apply whenever one comes across problems like these: For example, the extra electrons always goes to the atom that can support d orbitals (i.e. period 3 or higher elements)?
I wouldn't say that there are "hard & fast rules", especially since Lewis diagrams are actually gross simplifications of reality, and you have to do some quantum chemistry to really understand molecular structures. But you do need orbitals available to put in the extra electrons. And I think that symmetry is often a good guide also: were the F atoms able to gain extra electrons, that would result in a series of "ugly" resonance structures to account for all the possibilities.
 

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