How do I find the derivative of the square root of (2x+1) using the chain rule?

[tad.confused]

I need to find the derivative of the square root of (2x+1) (not sure how to do square root symbol here, sorry)

I understand that the square root of (2x+1)= (2x+1)^(1/2), but I am getting a little confused on how to continue from there.

 

[MillerGenuine]

From (2x+1)^(1/2) you should use the chain rule. take the derivative of the inside and multiply it by the derivative of the outside, when taking derivative of outside use substitution.