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Homework Help: How do I find the force in each member?

  1. Nov 13, 2014 #1
    1. The problem statement, all variables and given/known data
    Determine the force in each member of the truss. State if the members are in tension or compression.
    P1 = 450 lb, P2 = 600 lb
    2. Relevant equations

    3. The attempt at a solution
    No matter what I try I get wrong answers. I need someone to get me going in the right direction.

    Attached Files:

  2. jcsd
  3. Nov 13, 2014 #2
    First use trigonometry to calculate all the angles of the triangles, then sum the forces in the y direction and sum the moments about point a to solve for your reaction forces at a and c. then you can make cuts around different joints and do free body diagrams to solve for all the internal forces.

    Edit: also sum the forces in the x-direction to solve for the reaction force in the x direction at a
    Last edited: Nov 13, 2014
  4. Nov 13, 2014 #3
    How do I sum the forces in the y direction when I only know one of the forces, the 600 lbs?
  5. Nov 13, 2014 #4
    I did the torque about A. M = -450(3.46)+Fc(6)

    tan(30) = 0pp./6

    to get 3.46 ft.

    M = 259.5 ft*lb
  6. Nov 13, 2014 #5
    Sum the moment about point A and set equal to zero to get an equation in terms of only the y reaction at point C.
  7. Nov 13, 2014 #6
    259.5 is the value of the force at C in the y direction not the torque(Torque is the same as moment)

    Knowing that, sum the forces in the y direction and solve for point a
  8. Nov 13, 2014 #7
    This is the work done so far, thanks in advance you have been great help.

    My last question, how do I find the force at BE?

    Attached Files:

  9. Nov 13, 2014 #8
    Looks like you need to set up the equations for the joints B, D, and E. You'll have three unknowns: Fbd, Fbe, and Fde. You'll also have enough equations to plug in for and solve for them. It won't be as analytic as finding the other joints, but it will work. If you need help with that or any more further explaining let me know
  10. Nov 13, 2014 #9
    I'm confused since CD and DE are collinear they both have the value of 519lb. DB is 0 because it is part of a collinear member. So isn't my only unknown BE?
  11. Nov 13, 2014 #10
    Give me a second I'll work the math out really quickly.
  12. Nov 13, 2014 #11
    Your joint D math is incorrect, you still have to take into account that there are three members, and you have to include DE in your x and y calculations

    If you set up equations in the x and y for points B, D, and E, you should have three unknowns and three equations, and be able to solve for them. Each point has two trusses that are unknown. Just because CD and DE are colinear does not mean they are the same value. Only if there was no point in between then with a truss going down would they be equal to each other always
  13. Nov 13, 2014 #12
    Could you elaborate? I want to make sure I understand this. The answer key says CD and DE are equal, and going by my notes it says collinear members are equal.

    As far as setting up a systems, Basically you are saying to take my x and y of each point and combine them so I get 3 equations?
  14. Nov 13, 2014 #13
    What he is saying is that you need to take in account all three members attached to joint D because we have three internal forces compressing or in tension around joint D. Draw a FBD of joint D with all the internal forces around it. If only know one internal force you can make a system of equations to solve for the two unknowns. Sum of the forces in x and sum of the forces in y to make the two equations.
    Last edited: Nov 13, 2014
  15. Nov 13, 2014 #14
    ^ This
    Just sum the x and y direction for points B,D, and E. you wont be able to solve for the internal sections with just one point. you need to set up multiple equations and solve in terms of one force, and plug that into another equation

    Lets say you solve for the x and y in point B and get
    Fbe = Fbc - Fbd (these are just theoretical values, NOT the actual answer)

    Solving point d, we'd get:
    Fdb = Fde + 2*Fdc

    Solving Point E gives:
    Fed = Fea + Feb + 450

    You know Fbc, Fdc, and Fea. Other than that, just plug one value in and solve for the three values with the three equations
  16. Nov 13, 2014 #15
    So you can find Fed and Feb with a system of equations, but you need to solve for bata and alpha

    Attached Files:

    • pic1.pdf
      File size:
      80.2 KB
  17. Nov 13, 2014 #16
    I did end up getting the answer. Thanks guys for putting in the time to help me.
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