How do I find the inverse of a log function?

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To find the inverse of the function f(x) = log2(x) + 3, one should first let u = log2(x) and solve the equation for x before swapping x and f(x). The domain of the logarithmic function is x > 0, while the range is all real numbers. The discussion clarifies that the incorrect attempts involved misunderstanding logarithmic properties, specifically the difference between division and subtraction of logs. It emphasizes that the domain of the rational function must also avoid values that make the denominator zero. The user still struggles with finding the inverse despite the guidance provided.
hancyu
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Homework Statement



f(x) = log2 x + 3
2 log2 x − 1
how do i find the inverse of this? how do i find the range and domain of a log function?

Homework Equations

f(x) = log2 x + 3
2 log2 x − 1

is equal to
f(x) = log2 x + 3 - log2 (x − 1)2

D of f(x) = R of f-1(x)

The Attempt at a Solution



i tried changing the base but it didnt work...
 
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also, is the inverse of

f(x) = 2x−1 + 3

log2 (x/3) +1 = y


f(x) = log2/3(x − 2) − 4

(2/3)x+4 + 2 = y

are these correct?
 
Ok. Your attempt was sadly, incorrect, although similar to something you were probably thinking of:

\log_c ( \frac{a}{b} ) = \log_c a - \log_c b,

which is not the same as what you tried: \frac{ \log_c a}{\log_c b} = \log_c a - \log_c b, which is not true.

It might help if you let u= log_2 x so that you may view the problem easier. Doing so, solve the equation you have for you, replace the expression in x back in and solve it for x. Then swap your x and f(x), that's your inverse function!

For your second problem, not quite. Solve it for x first. So First take 3 to the other side,

2^{x-1} = f(x) - 3. After that, take log_2 of both sides, hopefully you can see the rest. Then just swap x for f(x).

The last one looks correct, good work =]
 
Presumably you know that the domain and range of any function of the form loga(x) is {x|x> 0} and all real numbers respectively.

You also should know that the domain of a rational function is all numbers such that the denominator is not zero.

Putting those together, the domain of loga(f(x))/loga(g(x)) is all x such that x is positive and g(x) is not 1 (so that log(g(x)) is not 0).
 
HallsofIvy said:
Presumably you know that the domain and range of any function of the form loga(x) is {x|x> 0} and all real numbers respectively.

You also should know that the domain of a rational function is all numbers such that the denominator is not zero.

Putting those together, the domain of loga(f(x))/loga(g(x)) is all x such that x is positive and g(x) is not 1 (so that log(g(x)) is not 0).

so the domain of the 1st one is x=>0 ? because log can never be zero or negative?

i still can't get the inverse tho...
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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