How do I find the slope of the tangent line using Definition 1 and Equation 2?

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Homework Help Overview

The problem involves finding the slope of the tangent line to the curve y=x³ at the point (-1,-1) using two different definitions of the derivative. The original poster expresses confusion regarding the calculations and the purpose of the exercise.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply both definitions of the derivative but encounters difficulties, particularly with the limit calculations. Some participants suggest factoring the numerator to resolve the indeterminate form encountered in the first definition.

Discussion Status

Participants are actively engaging with the original poster's attempts, providing hints about factoring and expanding expressions. There is a focus on clarifying the mathematical concepts involved, but no consensus has been reached regarding the specific methods to complete the calculations.

Contextual Notes

The original poster mentions using a limit calculator, indicating possible constraints in their understanding of limit evaluation. There is also a discussion about the definitions of indeterminate forms and the need for algebraic manipulation to resolve them.

metalmagik
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Homework Statement


Find the slope of the tangent line to the curve y=x3 at point (-1,-1)
(i) Using Definition 1
m=limx-->a[tex]\frac{f(x)-f(a)}{x-a}[/tex]

(i) Using Equation 2
m=limh-->0[tex]\frac{f(a+h)-f(a)}{h}[/tex]


Homework Equations





The Attempt at a Solution


For the first one, I got as far as limx-->-1x3+1/x+1 and was stuck. I thought it was undefined. Then I plugged it into a limit calculator online in desperation, and found that the answer was 3. But for equation 2 I got to the end and go undefined again, plugged it into the limit calculator seeing that it said it was undefined too. I just want to know how you would go about completing the first one, and I am just a little confused at the point of this exercise. Thanks for any help you guys can give me.
 
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for the first one, try factoring numerator. You should find that things cancel out. And by the way, it's not undefined, it's in an "indeterminate form". And for the second one, expand the numerator, and again, you'll find that things cancel out. :)
 
how do I factor x3+1...its not (x+1)3
 
metalmagik said:
how do I factor x3+1...its not (x+1)3

[tex]a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]

[tex]a^3+b^3=(a+b)(a^2-ab+b^2)[/tex]
 

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