How Do I Find the Tension in the Cable AB Given Forces and Angles?

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The discussion focuses on calculating the tension in cable AB by ensuring the net moment about hinge axis CD is zero, given forces F and P. The force P is specified as 65 lb, with direction angles beta at 37 degrees and gamma at 165 degrees. The unit vector for CD is defined as {0i + 0.8j + 0.6k}, while the force vector for F is given as F(ab){-0.43i + 0.29j + 0.86k}. Participants seek clarification on determining the third coordinate direction angle for force P and the appropriate radius for the cross product.

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(Figure is attached) Find the tension in the cable AB such that the net moment about the hinge axis CD induced by the forces F and P is zero. The force F is applied at point A and the force P is applied at point E. The magnitude of the force P is P = 65 lb. Two coordinate direction angles for the force P are known: beta = 37 degrees and gamma = 165 degrees. The hinged plate is rectangular.

- I found the unit vector CD {0i + 0.8j + 0.6k}
- I know that the force vector will be F(ab){-0.43i + 0.29j + 0.86k}

How do I find the third coordinate direction angle for the force P?
From there, what radius do I use for my cross product? I can pick any point on the line of action CD, correct?
 

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What is the definition of ##\beta## and ##\gamma##?
They are related to the direction of P somehow.

From there, what radius do I use for my cross product? I can pick any point on the line of action CD, correct?
The one closest to the point where P acts.
 

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