The 25-kg rectangular access door is held in the 90° open position by the single prop CD. Determine the force F in the prop and the magnitude of the force normal to the hinge axis AB in each of the small hinges A and B.[/B]
The Attempt at a Solution
I actually solved this problem entirely already. I used point A as the origin and I solved by first taking the sum of the moments about the y-axis (since A and B have zero moment arms there, and this just left the weight of the door and the force in the prop CD). I then used the same methods for the other axes until all the forces were found.
My question for everyone is: what works better and is more easier in this situation? Using the cross product or taking (F)(d)? I am having a debate with some of my classmates who think the cross product is a better approach. I think (F)(d) works better because all of the distances are already given in the problem and their would be no need to find position vectors and do lengthy cross products(I think that F(d) is much easier, since each cross product has a total of six separate products to compute). Let me know what you all think and how you might have solved it.
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