- #1
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using the integral, find the values of "p" so that the series converges
[tex]\sum[/tex]1/(ln(n)*np) (n=2 to ∞)
i had a similar question in which case i had
[tex]\sum[/tex]1/(x*lnpx)
[tex]\int[/tex]dx/(x*lnpx)
and there i simply said t=lnx dt=dx/x
[tex]\int[/tex]dt/tp
and from there it was really simple, but in the case of this question i have been trying and trying and just cant get it
[tex]\sum[/tex]1/(ln(n)*np) (n=2 to ∞)
i had a similar question in which case i had
[tex]\sum[/tex]1/(x*lnpx)
[tex]\int[/tex]dx/(x*lnpx)
and there i simply said t=lnx dt=dx/x
[tex]\int[/tex]dt/tp
and from there it was really simple, but in the case of this question i have been trying and trying and just cant get it