How do I rearrange the equation to solve for 'M'?

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Homework Help Overview

The discussion revolves around rearranging the equation T^2/R^3 = 4pi^2/GM to isolate the variable 'M'. Participants are exploring the correct transformations needed to achieve this goal.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss their attempts to rearrange the equation, questioning the correctness of their transformations. There is a focus on understanding how to properly move terms across the equation and the implications of doing so, particularly with fractions.

Discussion Status

The discussion includes various attempts at rearranging the equation, with some participants providing feedback on each other's reasoning. There is a recognition of the need to carefully consider the movement of terms, particularly in fractional form. While there is no explicit consensus, some guidance has been offered regarding the correct approach to isolating 'M'.

Contextual Notes

Participants express uncertainty about their understanding of rearranging equations and the rules governing such transformations. There is an acknowledgment of the challenges faced in this area, which may be influenced by prior experiences with similar problems.

Dark_Dragon
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well i have my equation T^2/R^3 = 4pi^2/GM

and i want to find 'M' on its own, (i never have been good at this) but here is my attempt:

M = 4pi^2/G(T^2/R^3)

is this correct?
 
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No (not as I read your notation). Note that when you "move" something like a/b to the other side of an equation it becomes b/a.

It may help to transform your equation only one step at a time. If you are in doubt about the transformation rules, then remember that you are transforming the two sides by doing the same thing on both sides, i.e. to "move" the term [itex]a[/itex] in [itex]a+b[/itex] you actually add [itex]-a[/itex] to both sides so that the original side becomes [itex]a-a+b = 0+b = b[/itex]; to "move" the factor [itex]a[/itex] in [itex]a \cdot b[/itex] you actually multiply with [itex]1/a[/itex] on both sides that on the original side becomes [itex](a/a) \cdot b = 1 \cdot b = b[/itex].
 
Last edited:
after having a look at it for a while, i tried one step at a time and i came out with:

M = (4*pi^2)(T^2/R^3)/G

is this any better? please don't take offence if i didnt understand your post.
 
Last edited:
This is the same result you got the first time, so its still not correct.

The problem is with [itex]T^2/R^3[/itex]. Originally that factor is on one side of the equation and must at some transformation step be moved to the other side. You seem to move it verbatim to the other side so it ends up being the same [itex]T^2/R^3[/itex] which is not correct.

Note that the factor is in the form of a fraction (i.e. a/b) and you should carefully consider what happens when you move such a fractional factor to the other side of an equation. If you have a textbook you may want to look up reciprocal.
 
so you're saying that i need to turn the expression into R^3/T^2?

then would the equation be:

M = (4pi^2)(R^3/T^2) / G ?

am i any closer?
 
You were initially correct in your first post, just remember to bring R^3 to the numerator to simplify things.
 
Dark_Dragon said:
so you're saying that i need to turn the expression into R^3/T^2?

then would the equation be:

M = (4pi^2)(R^3/T^2) / G ?

am i any closer?

Now it looks right, yes.
 
ok thank you very much :)
i have a fair bit of trouble with rearrangements,

so thanks for the help! =)
 

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