Varying mass- finding centripetal force

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Homework Help Overview

The discussion revolves around an experiment involving centripetal force, varying mass, and the relationship between period squared and mass. Participants are attempting to derive an experimental radius from a best fit slope obtained from a graph of T^2 versus mass, while keeping radius and centripetal force constant.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between T^2, mass, and centripetal force, questioning how to utilize the slope derived from their graph. There are inquiries about the experimental setup and the specific plots used in the analysis.

Discussion Status

Some participants are providing insights into the relationships between the variables and questioning the assumptions made regarding the constants in the experiment. There is an ongoing exploration of how to interpret the slope in relation to the known values of force and radius.

Contextual Notes

Participants are working under the constraints of a specific experimental setup where the centripetal force is represented by the weight of a calibration mass, and they are trying to reconcile their experimental findings with theoretical expectations. There is uncertainty regarding the correct interpretation of the slope and its implications for the radius calculation.

HexRei

Homework Statement


I have another problem with a similar thread title but they are not the same, I'd love help with either or both.

Ran trials with varying mass, but radius and centripetal force as constants. Must find experimental radius from the best fit slope. I have already finished the graph and found the slope. I know the slop is T^2/M, but I don't know how to use that.

Radius = .15
calibration weight 0.050
slope = 5.07

Homework Equations


F=4pi^2rM/T^2

The Attempt at a Solution



T^2=(4pi^2rM)/F I've tried rearranging it many ways but I can't figure out how to use this to determine radius from the slope.

4pi^2*.15M=1/F/T^2
5.92M= 1/F/T^2F*T^2=4pi^2rM
(F*T^2)M=4pi^2r
((F*T^2)M)/4pi^2=r
(.490*T^2)M) /39.47=r

Will subbing in mg for F do anything useful?
 
Last edited by a moderator:
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HexRei said:
Must find experimental radius from the best fit slope
of which plot ? You vary ##m## and measure ##T## so with the relationship ##T^2 = {4\pi^2mr\over F}## with fixed values for ##r## and ##F## you expect a slope ##T^2\over m## of ##{4\pi^2r\over F}##.

If you know either ##F## or ##r## you can determine the other; you can't determine both from one single slope...
 
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HexRei said:
Ran trials
Please describe the experiment.
HexRei said:
best fit slope
What did you plot against what? If you plotted y against x, rearrange your equation into the form y=cx. Whatever that gives for c is what the slope represents.
 
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Experiment was centripetal apparatus rotating with calibration weight representing Centripetal force (mg) and known mass M (calibration weight removed after calibration). Plot was T^2 vs mass. In this case we weren't looking for F (we know it from mg), just deriving r experimentally and seeing how it compares to our known measured r.
 
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Taking the equation T^2=4π^2rM/F

Can I just calculate 4π2r/F? When I plug in numbers I get 5.92M/F. Can I divide 5.92 by the known F of 4.90? When I do that I get 12.085 but M is still floating up there and the 12.085 isn't very close to my measured slope of 5.07.

And how do I get from here to F?

Thank you so much for the help!
 
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HexRei said:
When I plug in numbers I get 5.92M/F.
Not sure what you mean by M/F there. If you plug in numbers for r and F in 4π2r/F I would expect units s2/kg.
 

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