How do I show the 100N force is cartesian form?

Click For Summary
SUMMARY

The discussion focuses on converting a 100N force into Cartesian form using vector analysis. The user attempts to apply the equation M_y = u_y(r_y X F) but struggles with the initial steps. A suggested method involves redrawing the force in the x, y, and z directions and utilizing the right-hand rule to determine the moments about the y-axis. This approach simplifies the process of expressing the force in Cartesian coordinates.

PREREQUISITES
  • Understanding of vector notation and operations
  • Familiarity with Cartesian coordinates
  • Knowledge of the right-hand rule for vector cross products
  • Basic principles of static equilibrium and moments
NEXT STEPS
  • Study vector decomposition in Cartesian coordinates
  • Learn about the right-hand rule and its applications in mechanics
  • Explore the concept of moments about axes in three-dimensional space
  • Practice problems involving force vectors and their Cartesian representations
USEFUL FOR

Students in physics or engineering courses, particularly those focusing on mechanics, vector analysis, and statics. This discussion is beneficial for anyone needing to convert forces into Cartesian form for analysis.

suspenc3
Messages
400
Reaction score
0

Homework Statement



See attachment, I am getting everyone of these problems wrong.



Homework Equations



[tex]M_y = u_y(r_y X F)[/tex]

Where u=unit vector defining the direction of y axis
r=distance from y-axis to any point on the line of action of F
F=acting force



The Attempt at a Solution



I think I am going wrong right from the beginning, how do I show the 100N force is cartesian form? What I am doing is :

A=1.2i+0j+0k
B=0.6i+0.6j+1.2k

[tex] AB =\frac{ -0.6i+0.6j+1.2k}{\sqrt{0.6^2+0.6^2+1.2^2}}[/tex]

[tex] F_{AB} = (100N)\frac{ -0.6i+0.6j+1.2k}{\sqrt{0.6^2+0.6^2+1.2^2}}[/tex]

Im not going to bother to post the rest since I am pretty sure this isn't how to do this.

Thanks
 

Attachments

  • car1.JPG
    car1.JPG
    36.4 KB · Views: 493
Last edited:
Physics news on Phys.org
anyone?
 
Well there's a few ways you can do this. The easiest is to take a moment about the y-axis. You have the force in vector form now, so in your diagram you can redraw that force in the x,y,z direction. Then use the right-hand rule to decide which forces produce moments about the y-axis.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
Replies
15
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
3
Views
1K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
863