How do I simplify this fraction?

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Homework Help Overview

The discussion revolves around simplifying a fraction involving algebraic expressions. The original poster presents a specific expression and seeks clarification on the proper steps to simplify it, indicating some confusion about the formatting and components of the expression.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the correct interpretation of the expression and the steps involved in simplification. Questions arise regarding the handling of whole numbers in relation to fractions and the necessity of a common denominator when performing operations.

Discussion Status

Some participants provide guidance on the simplification process, noting the importance of maintaining a common denominator. There is a mix of interpretations and attempts to clarify the steps involved, with one participant expressing satisfaction with their understanding after testing their solution.

Contextual Notes

The original poster mentions that the question is not strictly a homework problem, indicating a desire for understanding rather than a direct solution. There is also a note about formatting issues in the expression presented.

TheTechNoir
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Okay so I am perplexed as to how I could be getting something so simple wrong and was wondering if I could be shown the proper steps/order for solving. It can be anything in this specific format, not anyone example. ex:

11[tex]\frac{(x + 4}{6}[/tex]) - 2 = ??

how do I simplfy? Thanks
also, those are supposed to be big brackets covering the whole fraction not just the numerator and ignore the closing bracket at end of the denominator... I haven't really written math on a pc before so I messed it up a bit. EDIT: Also, to further verify considering how it is incorrectly formatted, that 11 is not part of the fraction. Neither is the 2.
 
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So you are supposed to have

[tex] 11 \left( \frac{x+4} 6\right) - 2[/tex]

as the expression to simplify?

What answer did you get - that will help given an idea where you went astray.
 
Yup that is correct. Another example of it that I see (and have an answer for) is:

[tex] 2 \left( \frac{x+2} 6\right) - 6[/tex]

= [tex]\frac{x - 16}{3}[/tex]

I am misunderstanding something. I am getting the x over 3, but not the 16. I'm multiplying 2 and x for 2x, 2 and 2 for 4 so 2x + 4 all over 6. Which gives me x + 2 all over 3, then I subtract the 6 for x - 4 all over 3. Feel embarassed but have been racking my brain trying to come up with a method that could've been used to get the 16 and have attempted several different ways but never get the right answer.

PS: The reason I put this here and not homework help is it technically isn't a homework question... Dunno what the right decision was though I got hung up on technicalities. I'm doing inverse-functions homework and humerously enough I'm doing fine with everything else, but this is the one thing I can't seem to figure out which is also among the easiest.
 
Last edited:
You cannot just add or subtract the whole number from the fraction, you need to put it over the common denominator.
 
Okay so the step I'm not following is the - 3 * 6 all over 3.

How did you get that? I understand everything you wrote/how to do it, but I don't know where you got that part from.

EDIT: In response to Integral. Okay, that was what I had in mind that he might've been doing. And then you multiply the 6 by 3 because if you add something to the denominator you must also add it to the numerator in this case?
 
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[tex] 11 \left( \frac{x+4} 6\right) - 2[/tex]

= [tex]\frac{11x + 44}{6}[/tex] that being in brackets - 2

= [tex]\frac{11x + 44}{6}[/tex] - [tex]\frac{6 * 2}{6}[/tex]

= [tex]\frac{11x + 44 - 12}{6}[/tex]

= [tex]\frac{11x + 32}{6}[/tex]

EDIT: Yay, I just tested this and seem to have gotten the correct answer. If someone can confirm that'd be great, but pretty much sure I am doing it correctly now. Thanks very much!
 
That is correct.
 

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