How Do I Solve -0.874 = sin2θ in Physics?

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Homework Help Overview

The discussion revolves around solving the equation -0.874 = sin2θ, which involves trigonometric functions and angle isolation. The context is related to physics, particularly in understanding angles in motion or trajectories.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore how to isolate θ from the equation, with suggestions involving the inverse sine function. There are questions about the validity of using negative values in the sine function and the range of θ that should be considered.

Discussion Status

Participants are actively discussing the implications of the negative value in the sine function and the necessary range for θ. There is recognition that multiple solutions may exist, and some guidance has been offered regarding the interpretation of the problem.

Contextual Notes

There is uncertainty regarding the specified range for θ, which could affect the number of valid solutions. The original poster expresses frustration over potentially arriving at an incorrect answer after significant effort.

twenty5
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BLAHH! I can't figure this one out!

how do I isolate θ??

Statement is...

-0.874 = sin2θ


jeeebuss can someone walk me through LOL! I need it to finish off a 4 hour physics question =/
 
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Hi twenty5! :smile:

walk this way … if x = sinθ, then θ = sin-1x (or arcsin x) :wink:
 
tiny-tim said:
Hi twenty5! :smile:

walk this way … if x = sinθ, then θ = sin-1x (or arcsin x) :wink:

so, if -0.874 = sin2θ

then...
sin-1(-0.874) = 2θ

then...

(sin-1(-0.874))/2 = θ?
 
twenty5 said:
so, if -0.874 = sin2θ

then...
sin-1(-0.874) = 2θ

then...

(sin-1(-0.874))/2 = θ?

Yes, except …

i] it's normal to have only positive numbers inside the sin-1

ii] you didn't say what the range of θ was … did they specify 0 < θ < π or 2π or what? … there may be several solutions, especially since you're divding the angle by 2 :wink:
 
tiny-tim said:
Yes, except …

i] it's normal to have only positive numbers inside the sin-1

ii] you didn't say what the range of θ was … did they specify 0 < θ < π or 2π or what? … there may be several solutions, especially since you're divding the angle by 2 :wink:

hmm not sure because I'm using this to do this... https://www.physicsforums.com/showthread.php?t=293717

the very final post should be mine =P

right, since the football player is kicking the ball above ground on a horizontal plane (straight field), and he is kicking it forward to a distance other than where he is standing, it has to be somewhere between 0o and 89o

so, the answer I ended up with was -30.46o... so would that mean it is... wrong? LOL! omg... can't believe I spent 4 -5 hours to end up with a wrong answer -__- so depressing..
 
hmm … your minus sign seems to have come in post #18, but you don't show how you got it …

yes, you need an answer between 0 and 90º, but your formula should give you two such answers.

and I'm going to bed now … :zzz:​
 

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