How do I solve a quadratic equation with absolute value?

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SUMMARY

The discussion focuses on solving the quadratic equation involving absolute values: 25|x| = x^2 + 144. Participants suggest isolating |x| and breaking it into two cases: x ≥ 0 and x < 0. For x ≥ 0, the equation simplifies to 25x = x^2 + 144, while for x < 0, it becomes -25x = x^2 + 144. The solutions derived from these cases are x = ±16 and x = ±9, with emphasis on validating the solutions based on the defined conditions.

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Quinn Morris
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Homework Statement



25|x| = x^2 + 144



Homework Equations



none

The Attempt at a Solution



okay well, I'm not quite sure what to do, do i try to isolate the |x|? and then break it up into a positive and negative?

|x| = (x^2 + 144)/25 ?

but from here i become lost...
 
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Why not do what you just said? You have "isolated" |x|, now break it into positive and negative parts.

If x\ge 0 then |x|= x so the equation becomes x= (x^2+ 144)/25 or 25x= x^2+ 144. Solve that quadratic equation. Remember that only x\ge 0 are valid solutions.

If x< 0, then |x|= -x so the equation becomes -x= (x^2+ 144)/25 or -25x= x^2+ 144. Solve that quadratic equation. Remember that only x< 0 are valid solutions.

You might notice that it is easier to first break into two cases and then solve for x.
 
okay so should my answer be x = +/- 16, +/- 9?
 
Quinn Morris said:
okay so should my answer be x = +/- 16, +/- 9?

It's quite easy to check yourself =P Especially when checking one of the positive solutions gets rid of the negative counterpart as well.
 
k thx
 

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