How do I solve the following limit?

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The limit \(\lim_{x\rightarrow \infty} {\frac{3x+5}{x-4}}\) can be solved by dividing both the numerator and denominator by \(x\). This simplifies the expression to \(\lim_{x\to\infty} \frac{3+ \frac{5}{x}}{1- \frac{4}{x}}\). As \(x\) approaches infinity, the terms \(\frac{5}{x}\) and \(\frac{4}{x}\) approach 0, resulting in a final limit value of 3.

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BrainFood
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Could someone run me through how to solve this please? I am stuck.

\displaystyle\lim_{x\rightarrow \infty} {\frac{3x+5}{x-4}}​
 
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I worked it out. Never mind.
 
For others who might be interested, the simples thing to do is divide both numerator and denominator by "x":
\lim_{x\to\infty} \frac{3x+ 5}{x- 4}= \frac{3+ \frac{5}{x}}{1- \frac{4}{x}}

Now, as x goes to infinity, the terms with x in the denominator go to 0.
 

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