How Do I Solve This Moment Problem in My Assignment?

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SUMMARY

The discussion centers on resolving a moment problem in a physics assignment, specifically calculating the sum of moments. The user initially calculated a moment of 50.831 kN, while the correct answer is 58.513 kN. Key insights reveal that the vertical moment of Force B is zero due to its horizontal distance from the pivot being zero, and the correct horizontal moment calculation is 5.65 kN multiplied by the vertical distance from the pivot, yielding a moment of 16.97 kN. The total sum of moments is confirmed to be 58.4 kN when all components are accurately added.

PREREQUISITES
  • Understanding of basic trigonometry
  • Knowledge of moment calculations in physics
  • Familiarity with force diagrams and their components
  • Ability to interpret and analyze assignment problems
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  • Review the principles of calculating moments in physics
  • Study the method for resolving forces and moments in static equilibrium
  • Learn how to create and interpret force diagrams effectively
  • Practice solving similar moment problems using various examples
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Students in physics or engineering courses, particularly those tackling assignments involving moments and forces, as well as educators looking for examples of common student challenges in understanding these concepts.

Rammunition
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Hello I'm new :)
I'm stuck on my assignment on moments.

Homework Statement



Now i have attached a copy of my assignment paper which I scanned. Here is the link

scan00021.jpg



Now the horizontal and vertical forces sum is correct. But when I try to do the sum of moments I get 50.831 Kn when the answer should be 58.513 Kn. My lecturere gave me the answers but he said you have to show your working out so that you get it yourself.


Homework Equations



Triganometry, moments.

The Attempt at a Solution



see given link.


Help!
 
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This link shows the drawing better

scan0002-1.jpg


I have to determine the magnitude, direction and sense of the resultant and equilibrant forces acting on the component show in figur 1 (link above) and the perpendicular distance from their line of action from point z. But I am stuck on getting the total sum of forces.
 
If you want me to go through the whole problem let me know..

But the problem with your solution is with Force B.
Under your moment column for this force you have 5.65 x 0 = 0. This is incorrect.

The VERTICAL moment of force B IS ZERO! Since the hozitonal distance from Fb to the pivot is 0.

The HORIZTONAL moment would be 5.65 x (Vertical Distance from Pivot which is 3) , Giving you a horizontal moment of 16.97.

Add these all together and you have (16.97 + 30.03) + (6 + 5.472) = 58.4


I have a hard time reading your table, and I've never used that method, but if you don't understand my solution I'll try it your way.
 

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