How Do I Solve This Natural Logarithm Problem?

[empty.soul]

Homework Statement

This is my first time ever posting anything on here...but we just started working with ln? I know that it's the base e? or something like that...
but the problem is this...

1/3=ln(x^2/x-4)

Homework Equations

The Attempt at a Solution

I haven't attempted..i don't know how to do it o.o

 

[ideasrule]

ln is the opposite of "e to the power of", just like how addition is the opposite of subtraction. That is, if you raise e to the power of a certain number, taking the ln of the result gives you back the original number.

I presume you have to solve for x in 1/3=ln(x^2/x-4). I'll get you started: what happens when you raise e to the power of both sides? That is, e^(1/3)=e^(ln(x^2/x-4)), which simplifies to...