Why am I not getting the correct natural frequency?

8 replies · 3K views · last reply
EastWindBreaks
Messages
128
Reaction score
3

Homework Statement


Spreadsheet table of cantilever beam parameters: cross-sectional area 0.13 in^2, Young's modulus 10000000 psi, total length 26.56 inches, active length 12.4 inches, width 1.0 inch, thickness 0.13 inches, mass 148 g, moment of inertia 1.033 in^4 (0.000183), density 42.86 g/in^3.

To find the natural frequency of a uniform cantilever beam, the area moment of inertia, cross-sectional area and density are not given, everything else is given by the lab, our group got a theoretical natural frequency( it might be angular frequency) of 27.44 Hz from lab's computer with the same mass, dimensions and Young's modulus. however, when I try to solve it manually using the natural frequency equation, I got 1.195 as the natural frequency and 7.51 for the angular frequency. which is way off from 27.44, but I should be getting the same value. can someone confirm if my calculation is correct base on the data? I have tried countless times and its driving me crazy. our experimental natural frequency is 24.94, I am not sure how am I gona justify the huge error for the lab report.
2. Relevant equation
Equation for the natural angular frequency of a cantilever beam: omega_i = (xi_i / L)^2 times the square root of EI divided by rho A.

ξi=3.516 for Mode 1

Equation showing angular frequency omega equals 2 pi over T, which equals 2 pi times f.

I=bh^3/12

The Attempt at a Solution

 
Attachments
  • Spreadsheet table of cantilever beam parameters: cross-sectional area 0.13 in^2, Young's modulus 10000000 psi, total length 26.56 inches, active length 12.4 inches, width 1.0 inch, thickness 0.13 inches, mass 148 g, moment of inertia 1.033 in^4 (0.000183), density 42.86 g/in^3.
    upload_2017-11-23_1-5-6.png
    4 KB · Views: 1,189
  • Equation for the natural angular frequency of a cantilever beam: omega_i = (xi_i / L)^2 times the square root of EI divided by rho A.
    upload_2017-11-23_1-5-34.png
    1.7 KB · Views: 1,015
  • Equation showing angular frequency omega equals 2 pi over T, which equals 2 pi times f.
    upload_2017-11-23_1-8-37.png
    674 bytes · Views: 1,029
EastWindBreaks said:

Homework Statement


View attachment 215477
To find the natural frequency of a uniform cantilever beam, the area moment of inertia, cross-sectional area and density are not given, everything else is given by the lab, our group got a theoretical natural frequency( it might be angular frequency) of 27.44 Hz from lab's computer with the same mass, dimensions and Young's modulus. however, when I try to solve it manually using the natural frequency equation, I got 1.195 as the natural frequency and 7.51 for the angular frequency. which is way off from 27.44, but I should be getting the same value. can someone confirm if my calculation is correct base on the data? I have tried countless times and its driving me crazy. our experimental natural frequency is 24.94, I am not sure how am I gona justify the huge error for the lab report.
2. Relevant equation
View attachment 215478
ξi=3.516 for Mode 1

View attachment 215479
I=bh^3/12

The Attempt at a Solution

Please post your whole calculation.
 
  • Like
Likes   Reactions: EastWindBreaks
haruspex said:
Please post your whole calculation.

angular frequency of mode 1= (3.516/12.4^2)* sqrt((1*10^7)*(0.000183)/42.86/0.13)
ω= (3.516/12.4^2) * sqrt(328.44)
ω= 0.02287* 18.1229
ω=0.4144

where 0.000183 is the area moment of inertia which came from (bh^3)/12, (1)(0.13^3)/12=0.000183
density=mass/volume=148/(0.13*1*26.56)=42.86

I forgot to square root when I initially post the thread, however, this time, the angular frequency is even smaller.
 
EastWindBreaks said:
angular frequency of mode 1= (3.516/12.4^2)* sqrt((1*10^7)*(0.000183)/42.86/0.13)
ω= (3.516/12.4^2) * sqrt(328.44)
ω= 0.02287* 18.1229
ω=0.4144

where 0.000183 is the area moment of inertia which came from (bh^3)/12, (1)(0.13^3)/12=0.000183
density=mass/volume=148/(0.13*1*26.56)=42.86

I forgot to square root when I initially post the thread, however, this time, the angular frequency is even smaller.
I do not see any units conversion. All the distances are in inches, so that's ok, but you have force in pounds weight and density using grams.
 
  • Like
Likes   Reactions: EastWindBreaks
haruspex said:
I do not see any units conversion. All the distances are in inches, so that's ok, but you have force in pounds weight and density using grams.
oh wow, yeah, I didnt do units conversion because they were all in inches but I totally forgot about grams and lbs. ok so this time, the mass is 0.3263 pound, density= 0.3263/(0.13*1*26.56)= 0.0945 lb/in^3, the new angular frequency I got using this new density is 8.828 Hz, which is still way off...
 
EastWindBreaks said:
the mass is 0.3263 pound,
In E, it is pounds weight, i.e. a force. That has dimension MLT-2. To be consistent, that L needs to be in inches, so you need a factor g in in/s2.
(Why does anyone use a system other than MKS?)
 
  • Like
Likes   Reactions: EastWindBreaks
haruspex said:
In E, it is pounds weight, i.e. a force. That has dimension MLT-2. To be consistent, that L needs to be in inches, so you need a factor g in in/s2.
(Why does anyone use a system other than MKS?)
oh right, you mean convert gram to slug right? so, mass= 0.0101412 slug, density = 0.0101412/(0.13*26.56*1)=0.003016 slug/in^3
and I got 49.4 Hz for angular frequency, 7.86 for the natural frequency. still off from 27.44...
yeah, I wish the world can use a single unit system...we have the U.S unit system, SI, and British unit system..
 
EastWindBreaks said:
convert gram to slug right? so, mass= 0.0101412 slug,
I don't think that quite fixes it. The ratio of slug to pound mass, 32 roughly, is based on the value of g when expressed in ft/s2. Your change is equivalent to multiplying the E value by 32, which would be right for converting from pounds weight /sq into lb ft s-2in-2. But everywhere else in your calculation distance are in inches, so you need E in lb s-2 in-1. I.e. rather than express the density in slugs multiply E by 32 x 12.
 
  • Like
Likes   Reactions: EastWindBreaks
Thank you very much! I finally got it, I sometimes completely forgot which unit system is which...the pound force, pound mass, slug are so confusing and unfriendly for students.
Spreadsheet table of beam properties in US units and SI units: volume, cross-sectional area, Young's Modulus, length 26.56 inches, active length 12.4 inches, width 1.0 inch, thickness 0.13 inch, mass 148 g, moment of inertia 1.033 in^4, density 42.86 g/in^3, and mode 1 angular frequency 173.4573 rad/s.
 
Attachments
  • Spreadsheet table of beam properties in US units and SI units: volume, cross-sectional area, Young's Modulus, length 26.56 inches, active length 12.4 inches, width 1.0 inch, thickness 0.13 inch, mass 148 g, moment of inertia 1.033 in^4, density 42.86 g/in^3, and mode 1 angular frequency 173.4573 rad/s.
    upload_2017-11-24_3-11-8.png
    8.1 KB · Views: 546